从数组+对象创建嵌套的UL LI的PHP函数
问题描述:
我有这样的数组+对象。从数组+对象创建嵌套的UL LI的PHP函数
Array
(
[0] => stdClass Object
(
[tid] => 1
[parent_id] => 0
[language] => th
[t_type] => category
[t_name] => cat1
[t_description] =>
[t_uri] => cat1
[t_uri_encoded] => cat1
[t_uris] =>
[meta_title] =>
[meta_description] =>
[meta_keywords] =>
[childs] => Array
(
[0] => stdClass Object
(
[tid] => 3
[parent_id] => 1
[language] => th
[t_type] => category
[t_name] => cat1.1
[t_description] =>
[t_uri] => cat1.1
[t_uri_encoded] => cat1.1
[t_uris] =>
[meta_title] =>
[meta_description] =>
[meta_keywords] =>
[childs] => Array
(
[0] => stdClass Object
(
[tid] => 5
[parent_id] => 3
[language] => th
[t_type] => category
[t_name] => cat1.1.1
[t_description] =>
[t_uri] => cat1.1.1
[t_uri_encoded] => cat1.1.1
[t_uris] =>
[meta_title] =>
[meta_description] =>
[meta_keywords] =>
)
)
)
[1] => stdClass Object
(
[tid] => 4
[parent_id] => 1
[language] => th
[t_type] => category
[t_name] => cat1.2
[t_description] =>
[t_uri] => cat1.2
[t_uri_encoded] => cat1.2
[t_uris] =>
[meta_title] =>
[meta_description] =>
[meta_keywords] =>
)
)
)
[1] => stdClass Object
(
[tid] => 2
[parent_id] => 0
[language] => th
[t_type] => category
[t_name] => cat2
[t_description] =>
[t_uri] => cat2
[t_uri_encoded] => cat2
[t_uris] =>
[meta_title] =>
[meta_description] =>
[meta_keywords] =>
)
)
此数组+对象中JSON字符串
[{"tid":"1","parent_id":"0","language":"th","t_type":"category","t_name":"cat1","t_description":null,"t_uri":"cat1","t_uri_encoded":"cat1","t_uris":null,"meta_title":null,"meta_description":null,"meta_keywords":null,"childs":[{"tid":"3","parent_id":"1","language":"th","t_type":"category","t_name":"cat1.1","t_description":null,"t_uri":"cat1.1","t_uri_encoded":"cat1.1","t_uris":null,"meta_title":null,"meta_description":null,"meta_keywords":null,"childs":[{"tid":"5","parent_id":"3","language":"th","t_type":"category","t_name":"cat1.1.1","t_description":null,"t_uri":"cat1.1.1","t_uri_encoded":"cat1.1.1","t_uris":null,"meta_title":null,"meta_description":null,"meta_keywords":null}]},{"tid":"4","parent_id":"1","language":"th","t_type":"category","t_name":"cat1.2","t_description":null,"t_uri":"cat1.2","t_uri_encoded":"cat1.2","t_uris":null,"meta_title":null,"meta_description":null,"meta_keywords":null}]},{"tid":"2","parent_id":"0","language":"th","t_type":"category","t_name":"cat2","t_description":null,"t_uri":"cat2","t_uri_encoded":"cat2","t_uris":null,"meta_title":null,"meta_description":null,"meta_keywords":null}]
如何创建嵌套UL里这样。
<ul>
<li>cat1
<ul>
<li>cat1.1
<ul>
<li>cat1.1.1</li>
</ul>
</li>
<li>cat1.2</li>
</ul>
</li>
<li>cat2</li>
</ul>
这是我曾尝试
echo list_nested_cat($list_item);
function list_nested_cat($list_item, $start = 0) {
echo '<ul style="margin-left: 1em;">';
foreach ($list_item as $item) {
if (isset($item->childs) && is_array($item->childs)) {
echo '<li>'.$item->t_name.'</li>';
list_nested_cat($item->childs);
} else {
echo '<li>'.$item->t_name.'</li>';
}
}
echo '</ul>';
}
但这个函数不正确呼应HTML嵌套UL李格式。
ps。我从arnaud576875
PHP tree structure for categories and sub categories without looping a query
答
的代码中创建数组对象这应该让你开始:
它使用一个递归函数;它自称。
更新
测试了JSON对象,并修正了一些错误
<?php
echo make_ulli($object);
function make_ulli($array){
if(!is_array($array)) return '';
$output = '<ul>';
foreach($array as $item){
$output .= '<li>' . $item->t_name;
if(property_exists($item, 'childs'))
$output .= make_ulli($item->childs);
$output .= '</li>';
}
$output .= '</ul>';
return $output;
}
?>
+1
@vee现在它工作得很好。谢谢! – iambriansreed 2012-04-25 15:39:49
请张贴丑数组作为JSON字符串用于测试目的? – iambriansreed 2012-04-25 03:51:48
@iambriansreed我发布了JSON字符串,请求。 – vee 2012-04-25 09:14:19
@vee我用它来测试我的代码并修复了一些错误。查看发布的更新代码。 – iambriansreed 2012-04-25 15:40:24