解析与jQuery
答
jQuery.get('myxml.xml', function(xml){
var result = jQuery(xml).text();
alert(result);
});
答
$.ajax({
url: '/foo.xml',
success: function(xml) {
alert($(xml).find('result').text());
}
});
哦。我感到非常愚蠢:-)谢谢jp! – Roberto 2010-07-16 14:50:13