STL映射在搜索尝试时抛出错误
问题描述:
我想创建一个充满字符串作为键和整数值的映射。当我尝试使用它进行搜索时,问题就开始了。有人能告诉我我错了哪里?我是否在同一个陈述中有两个地图?STL映射在搜索尝试时抛出错误
invale is "ale"
roomno = 2;
// roomlist is a map
// rinventory is another map
if(roomlist[roomno].rinventory.find(invale) != map<string, int>::end());
我得到的错误如下。什么重载功能?这确实是一个漫长的错误。
error C2668: 'std::_Tree<_Traits>::end' : ambiguous call to overloaded function
1> with
1> [
1> _Traits=std::_Tmap_traits<std::string,int,std::less<std::string>,std::allocator<std::pair<const std::string,int>>,false>
1> ]
1> c:\program files\microsoft visual studio 9.0\vc\include\xtree(569): could be 'std::_Tree<_Traits>::const_iterator std::_Tree<_Traits>::end(void) const'
1> with
1> [
1> _Traits=std::_Tmap_traits<std::string,int,std::less<std::string>,std::allocator<std::pair<const std::string,int>>,false>
1> ]
1> c:\program files\microsoft visual studio 9.0\vc\include\xtree(564): or 'std::_Tree<_Traits>::iterator std::_Tree<_Traits>::end(void)'
1> with
1> [
1> _Traits=std::_Tmap_traits<std::string,int,std::less<std::string>,std::allocator<std::pair<const std::string,int>>,false>
1> ]
1> while trying to match the argument list '(void)'
在此先感谢您。
答
尝试将其更改为:
if(roomlist[roomno].rinventory.find(invale) != roomlist[roomno].rinventory.end());
答
应该
if(roomlist[roomno].rinventory.find(invale) != roomlist[roomno].rinventory.end());
答
map::end()
方法也不是一成不变的。
正确的方法是这样的:
map<string, int>::iterator it = roomlist[roomno].rinventory.find(invale);
if(it != roomlist[roomno].rinventory.end())
// do stuff
谢谢您的帮助 – 2011-12-17 09:06:03