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春季安全启动404

分类: 技术问答 • 2022-07-11 23:43:16
问题描述：

我有一个问题：我从http://docs.spring.io/spring-security/site/docs/5.0.0.BUILD-SNAPSHOT/reference/htmlsingle/#samples春季安全启动404

下载的文件，它的我的web.xml：

<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"> 
    <context-param> 
     <param-name>contextConfigLocation</param-name> 
     <param-value>/WEB-INF/security.xml</param-value> 
    </context-param> 

    <welcome-file-list> 
     <welcome-file>index.jsp</welcome-file> 
    </welcome-file-list> 

    <filter> 
     <filter-name>springSecurityFilterChain</filter-name> 
     <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> 
    </filter> 

    <filter-mapping> 
     <filter-name>springSecurityFilterChain</filter-name> 
     <url-pattern>/*</url-pattern> 
    </filter-mapping> 

    <listener> 
     <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> 
    </listener>  
</web-app>

security.xml文件：

<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:security="http://www.springframework.org/schema/security" xsi:schemaLocation="http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.0.xsd"> 
    <security:http auto-config="true"> 
     <security:intercept-url pattern="/products/add" access="ROLE_ADMIN" /> 
     <security:form-login login-page="/login" default-target-url="/products/add" authentication-failure-url="/loginfailed"/> 
     <security:logout logout-success-url="/logout" /> 
    </security:http> 
    <security:authentication-manager> 
     <security:authentication-provider> 
      <security:user-service> 
       <security:user name="Admin" password="Admin123" authorities="ROLE_ADMIN" /> 
      </security:user-service> 
     </security:authentication-provider> 
    </security:authentication-manager> 
</beans>

我收到错误404，如果我尝试进入我的网站，有什么不对？

答

您还没有为您的应用程序定义任何servlet。尝试为该servlet定义DispatherServlet和映射。

答

是否有人可以推荐我任何春季的好教程？因为我失去了力量。我以前从未遇到.NET或PHP的任何框架问题，但Java冒险活动已经失去动力。我尝试从教程中的例子，它不工作，这是不正常的。我使用linux和tomcat8，也许在这是问题？

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