如何将JSON对象转换为Python对象?
问题描述:
json_str = '{"name":"Saeron", "age":23, "score":100}'
def json2dict(d):
return dict(d['name'],d['age'],d['score'])
d = json.loads(json_str, object_hook=json2dict)
print(d.name)
却得到一个错误:
Traceback (most recent call last):
File "C:/Users/40471/PycharmProjects/untitled/untitled.py", line 693, in <module>
d = json.loads(json_str, object_hook=json2dict)
File "C:\Program Files\Python36\lib\json\__init__.py", line 367, in loads
return cls(**kw).decode(s)
File "C:\Program Files\Python36\lib\json\decoder.py", line 339, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "C:\Program Files\Python36\lib\json\decoder.py", line 355, in raw_decode
obj, end = self.scan_once(s, idx)
File "C:/Users/40471/PycharmProjects/untitled/untitled.py", line 692, in json2dict
return dict(d['name'],d['age'],d['score'])
TypeError: dict expected at most 1 arguments, got 3
我遵循的指示unpickle一个JSON obj转换为一个Python obj中的步骤,就像这样:
json_str = '{"age": 20, "score": 88, "name": "Bob"}'
print(json.loads(json_str, object_hook=dict2student))
为什么不能在字典中生效?我该如何修改?
答
一旦您使用d = json.loads(json_str)
加载json d是python字典 您无法使用。(点)获取该项目。
您需要:
json_str = '{"name":"Saeron", "age":23, "score":100}'
d = json.loads(json_str)
print(d['name'])
答
json.loads可以直接评估你的字符串作为一个Python解释如下:
json_str = '{"name":"Saeron", "age":23, "score":100}'
d = json.loads(json_str)
print(d['name'])
>>>Saeron
您通过object_hook参数传入通过该功能将收到这是字典从给定的字符串创建输入
删除'object_hook',你并不需要它。 –
或者,您可以使用'return dict(** d)',但它是多余的,因为'json.loads'会自动将您的json转换为字典。 –