HTTP状态500 - java.lang.NumberFormatException:null
问题描述:
我正在创建一个标准的动态Web项目,包括一个Servlet,一个过滤器来过滤请求和jsp页面。 我从welcome.jsp中获取书籍的数量,并根据计数我在add.jsp上填充输入框。我想过滤通过add.jsp传来的数据。当我通过Regex验证数据时,显示错误。我的流程也是正确的,即从开始的FILTER - > CONTROLLER - > FILTER - > PAGE等等。HTTP状态500 - java.lang.NumberFormatException:null
错误: java.lang.NumberFormatException:空
完整跟踪是这样的:
HTTP Status 500 - java.lang.NumberFormatException: null
type Exception report
message java.lang.NumberFormatException: null
description The server encountered an internal error that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: java.lang.NumberFormatException: null
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:549)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:470)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
com.filter.RequestFilter.doFilter(RequestFilter.java:107)
root cause
java.lang.NumberFormatException: null
java.lang.Integer.parseInt(Unknown Source)
java.lang.Integer.parseInt(Unknown Source)
org.apache.jsp.WEB_002dINF.add_jsp._jspService(add_jsp.java:139)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
com.filter.RequestFilter.doFilter(RequestFilter.java:107)
的代码,其中其表现是:
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
// TODO Auto-generated method stub
// place your code here
boolean flag = true;
HttpServletRequest httpServletRequest = (HttpServletRequest) request;
HttpServletResponse httpResponse = (HttpServletResponse) response;
httpServletRequest.getServletPath();
System.out.println(httpServletRequest.getServletPath());
String address = InetAddress.getLocalHost().getHostAddress();
System.out.println(address);
// For the first time (Welcome page) i will be 0 so that it will perform first if
if(i == 0)
{
System.out.println(i);
if(verify(address))
{
chain.doFilter(request, response);
i++;
}
else
{
RequestDispatcher requestDispatcher = httpServletRequest.getServletContext().getRequestDispatcher("/WEB-INF/forbidden.jsp");
requestDispatcher.forward(request, response);
return;
}
}
// For the second time (Controller) i will be 1 so that it will perform first if
else if(i == 1)
{
System.out.println(i);
i++;
System.out.println("after ++"+i);
chain.doFilter(request, response);
}
// For the second time (add page) i will be 2 so that it will perform first if
else if(i == 2)
{
if(specialChara(httpServletRequest))
{
System.out.println(i);
System.out.println("done");
i++;
chain.doFilter(request, response);
}
else
{
System.out.println(i);
flag = false;
System.out.println(""+httpServletRequest.toString()+ "\n"+httpResponse.toString());
RequestDispatcher requestDispatcher = httpServletRequest.getServletContext().getRequestDispatcher("/WEB-INF/add.jsp");
requestDispatcher.forward(request, response);
}
}
// For the third time (Controller) i will be 2 so that it will perform first if
else if(i == 3)
{
System.out.println(i);
i++;
chain.doFilter(request, response);
i = 0;
}
它给e rror在循环中forward()的行,其中我= 2。 可能是什么问题? add.jsp的
链接https://docs.google.com/document/d/1fOzymYvlLXS577DrSrznRoeBnI7_hMmuqzFoK02xKoU/edit?usp=sharing
答
从堆栈跟踪似乎问题不在于你的java类,而是你的JSP。我的猜测是在线
int no = Integer.parseInt(request.getParameter("no"));
似乎不是null.Also最好使用和其他条件标签,而不是在JSP中使用scriptlet。
请问我该怎么做呢? 我应该将它存储到会话对象吗? – 2013-02-21 06:00:13
您应该调试为什么“否”为空。你在Java类的请求范围中设置了这个值吗? – HarshaKA 2013-02-24 05:05:28