XSLT混合内容节点

Question

我有一个相当愚蠢的问题。我如何确保我的XML混合内容节点不会混淆？例如，我有一个类似这样的XML结构。

<root> 
<book> 
    <title>Stuff</title> 
    <description> This book is <i>great</i> if you need to know about stuff. 
       I suggest <link ref="Things">this one</link> if you need to know 
       about things. </description> 
</book> 
[other books] 
</root> 

我需要的最终内容，看起来像这样

<h1>List of books</h1> 
<h2><a name="Stuff"/>Stuff</h2> 
<p> This book is <i>great</i> if you need to know about stuff. 
    I suggest <a href="#Things">this one</a> if you need to know 
    about things. </p> 

但我不能提取文本节点的部分，我总是抢了整个事情。我正在使用后代轴。任何线索我做错了什么？

这里是我的XSLT：

<xsl:template match="description/*"> 
    <xsl:for-each select="following-sibling::*"> 
      <xsl:choose> 
      <xsl:when test="name(.)='link'"> 
       <a href="{@ref}"><xsl:value-of select="."/></a> 
      </xsl:when> 
      <xsl:when test="name(.)='em'"> 
       <em><xsl:value-of select="."/></em> 
      </xsl:when> 
      <xsl:otherwise><p><xsl:value-of select="."/></p></xsl:otherwise>  
     </xsl:choose> 
    </xsl:for-each> 
    </xsl:template> 

请注意，封闭的XML和HTML结果仅仅是例子，我不得不面对它，我不封闭在，为了清楚起见，一个更大的结构。

Answer 1

<xsl:apply-templates>是你的朋友：

<xsl:stylesheet 
    version="1.0" 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
> 
    <xsl:output method="html" /> 

    <xsl:template match="root"> 
    <h1>List of books</h1> 
    <xsl:apply-templates /> 
    </xsl:template> 

    <!-- a <book> consists of its <title> and <description> --> 
    <xsl:template match="book"> 
    <xsl:apply-templates select="title" /> 
    <xsl:apply-templates select="description" /> 
    </xsl:template> 

    <!-- <title> is turned into a <h2> --> 
    <xsl:template match="title"> 
    <h2> 
     <a name="{.}"/> 
     <xsl:value-of select="." /> 
    </h2> 
    </xsl:template> 

    <!-- <description> is turned into a <p> --> 
    <xsl:template match="description"> 
    <p> 
     <xsl:apply-templates /> 
    </p> 
    </xsl:template> 

    <!-- default rule: copy any node beneath <description> --> 
    <xsl:template match="description//*"> 
    <xsl:copy> 
     <xsl:copy-of select="@*" /> 
     <xsl:apply-templates /> 
    </xsl:copy> 
    </xsl:template> 

    <!-- override rule: <link> nodes get special treatment --> 
    <xsl:template match="description//link"> 
    <a href="#{@ref}"> 
     <xsl:apply-templates /> 
    </a> 
    </xsl:template> 

    <!-- default rule: ignore any unspecific text node --> 
    <xsl:template match="text()" /> 

    <!-- override rule: copy any text node beneath description --> 
    <xsl:template match="description//text()"> 
    <xsl:copy-of select="." /> 
    </xsl:template> 

</xsl:stylesheet> 

以下输出为您的输入XML生成（注：我用管道输送它通过整洁的可读性的原因不相关的空白了。删除过程中）：

<h1>List of books</h1> 
<h2><a name="Stuff">Stuff</h2> 
<p>This book is <i>great</i> if you need to know about stuff. I 
suggest <a href="#Things">this one</a> if you need to know about 
things.</p> 

Answer 2

<root> 
<book> 
    <title>Stuff</title> 
    <description><![CDATA[ 
     This book is <i>great</i> if you need to know about stuff. 
     I suggest <link ref="Things">this one</link> if you need to know 
     about things. 
    ]]></description> 
</book> 
[other books] 
</root>