访问对应值给出某个已知值

Question

假设我有一个数组类似下面：

Array 
(
    [0] => Array 
     (
      [id] => 1 
      [title] => Group1 
      [description] => This is the group1. 
     ) 

    [1] => Array 
     (
      [id] => 2 
      [title] => Group2 
      [description] => This is group2. 
     ) 

) 

假设标题被称为“组2”。如果我不能确定它的等效描述（即“这是group2”），如果它不知道其关键字，标识等仅有标题，我该如何确定？

感谢您的任何帮助。

Answer 1

试试这个：

$title = "Group2"; 

foreach($your_array as $val){ 
    if($val['title'] == $title){ 
     echo $val['description']; 
     break; //cut back on unnecessary looping 
    } 
} 

Answer 2

你必须遍历主阵列上，然后扫描该称号。

假设你的主数组被称为$groups：

$title = 'Group2'; 
foreach($groups as $key => $group){ 
    if ($group['title'] == $title){ 
    $groupDescription = $group['description']; 
    // if you need to reference this group again, save it's key. 
    $groupKey = $key; 
    } 
} 

您可以将break命令你找到你正在寻找终止循环，这样就不会继续扫描阵列组后后你找到了你正在寻找的那个。

Answer 3

尝试这样

foreach($myarray as $val){ 
    if($val['title'] == "Group2"){ 
    echo 'This is description '.$val['description']; 
    } 
}