如何创建r中像数据的数据结构(火山)
问题描述:
我有如下因素格式的一些数据:如何创建r中像数据的数据结构(火山)
y <- c(2637732, 2622262, 2637466, 2630985, 2620929, 2630888, 2625944, 2650034, 2645318, 2636731, 2629001, 2650776, 2648531, 2633905, 2654874, 2637571, 2650994, 2641130, 2652417, 2654005)
x <- c(756994.5, 760190.9, 760898.7, 761690.2, 763064.1, 763089.3, 765942.4, 767058.1, 768265.0, 768471.8, 771393.8, 771394.1, 775332.6, 778324.8, 780480.9, 780961.0,781001.5, 783904.7, 786200.6, 788007.5)
z <- c(0.008849558,0.260162602,0.115044248,0.109243697,0.066666667,0.000000000,0.022556391,0.157894737,0.045045045,0.378151261,0.028776978,0.128571429,0.064220183,0.148760331,0.514851485,0.173913043,0.019417476,0.037383178,0.041237113,0.150537634)
这里是我的代码进行插值数据
df <- data.frame(x=x,y=y,z=z);
gridint <- 500;
xmin <- signif(min(df$x),4) - 1000;
xmax <- signif(max(df$x),4) + 1000;
ymin <- signif(min(df$y),5) - 1000;
ymax <- signif(max(df$y),5) + 1000;
yo <- seq(ymin, ymax, length=gridint);
xo <- seq(xmin, xmax, length=gridint);
library(akima);
fld<- with(df, interp(x = x, y = y, z = z, linear = FALSE, extrap = TRUE, xo = xo, yo= yo));
fld2 <- as.data.frame(interp2xyz(fld));
我想创建一个像data(volcano)这样的结构来运行下面的脚本:
library(rgl);
data(volcano)
dim(volcano)
peak.height <- volcano;
ppm.index <- (1:nrow(volcano));
sample.index <- (1:ncol(volcano));
zlim <- range(peak.height)
zlen <- zlim[2] - zlim[1] + 1
colorlut <- terrain.colors(zlen) # height color lookup table
col <- colorlut[(peak.height-zlim[1]+1)] # assign colors to heights for each point
open3d()
ppm.index1 <- ppm.index*zlim[2]/max(ppm.index);
sample.index1 <- sample.index*zlim[2]/max(sample.index)
title.name <- paste("volcano plot3d", sep = "");
surface3d(ppm.index1, sample.index1, peak.height, color=col, back="lines", main = title.name);
grid3d(c("x", "y+", "z"), n =20)
sample.name <- paste("col.", 1:ncol(volcano), sep="");
sample.label <- as.integer(seq(1, length(sample.name), length = 5));
axis3d('y+',at = sample.index1[sample.label], sample.name[sample.label], cex = 0.3);
axis3d('y',at = sample.index1[sample.label], sample.name[sample.label], cex = 0.3)
axis3d('z',pos=c(0, 0, NA))
ppm.label <- as.integer(seq(1, length(ppm.index), length = 10));
axes3d('x', at=c(ppm.index1[ppm.label], 0, 0), abs(round(ppm.index[ppm.label], 2)), cex = 0.3);
title3d(main = title.name, sub = "test", xlab = "ppm", ylab = "samples", zlab = "peak")
rgl.bringtotop();
任何人都可以帮助我吗?一些忠告?
在此先感谢
答
首先,让我们用X,Y做到这一点,你开始与z值:
str(fld)
List of 3
$ x: num [1:50] 756000 756673 757347 758020 758694 ...
$ y: num [1:50] 2619900 2620635 2621369 2622104 2622839 ...
$ z: num [1:50, 1:50] 0.255 0.256 0.257 0.258 0.259 ...
,可以与底座的图形绘制功能persp
:
png(); with(fld, persp(x,y,z)) ; dev.off()
现在建立一个合适的rgl
阴谋,如果....我可以。事实证明,您需要将rgl
的坐标范围缩放到[0-1],使其具有正确的宽高比以查看任何内容。 (也可以用aspect3d(小提琴),但我已经有一个
open3d()
with(fld, surface3d((x -min(x))/(max(x) -min(x)),
(y -min(y))/(max(y) -min(y)),
(z -min(z))/(max(z) -min(z))))
rgl.snapshot("test.png")
答
跌跌撞撞您可以使用deldir
包基于原始数据显示的表面。帮助页面读的是?persp3d.deldir
library(rgl)
open3d()
plot3d(x, y, z) # Establish the axes, set labels etc. ...
library(deldir)
dxyz <- deldir(x, y, z = z, suppressMsge = TRUE)
col <- cm.colors(20)[1 + round(19*(z - min(z))/diff(range(z)))]
persp3d(dxyz, col = col, add = TRUE)
产生这样的结果:
如果您不想显示积分,则可以在plot3d
呼叫中使用type = 'n'
,或者完全跳过它并将add = TRUE
参数丢弃到persp3d
。后者使得设置宽高比和标题有点困难。
您似乎没有足够的积分来支持3d表面。这些数据是什么? –
数据是潜在模型(交互指数)的结果。我使用此代码来插入基础数据: df
我编辑了我的问题我用来插入这些数据的代码(x,y,z) –