如何使用硒从Postman读取Json数据

Question

我必须打开Postman并使用GET选项传递Url。它将生成一个Json数据。我必须阅读并与现有数据进行比较。 那么，任何人都可以帮助我？ 感谢

Answer 1

我了解你正在尝试在API响应回报JSON格式比较数据

此代码可以帮助你 -

import java.io.IOException; 
import java.net.HttpURLConnection; 
import java.net.MalformedURLException; 
import java.net.URL; 
import java.util.Scanner; 

import org.json.JSONArray; 
import org.testng.annotations.Test; 

public class WebAPITest 
{ 

    public static String url1="http://restcountries.eu/rest/v1";   

    @Test 
    public void getAPIRequest() throws Exception 
    { 
     try 
     {   
      URL url = new URL(url1);    
      HttpURLConnection conn = (HttpURLConnection) url.openConnection(); 
      conn.setRequestMethod("GET"); 
      conn.setRequestProperty("Accept", "application/json"); 
      if(conn.getResponseCode() != 200) 
      { 
       throw new RuntimeException(" HTTP error code : "+ conn.getResponseCode()); 
      } 
      Scanner scan = new Scanner(url.openStream()); 
      String entireResponse = new String();  
      while (scan.hasNext()) 

       entireResponse += scan.nextLine(); 

       System.out.println("Response : " + entireResponse); 

       scan.close(); 

       System.out.println("API response Code : " + conn.getResponseCode() +"\t" + conn.getResponseMessage()); 

       JSONArray jsonarray = new JSONArray(entireResponse); 

      for (int i = 0; i < jsonarray.length(); i++) 
      { 

       String countryname = jsonarray.getJSONObject(i).getString("name"); 
       System.out.println("Country name : " + countryname); 

       JSONArray languages = jsonarray.getJSONObject(i).getJSONArray("languages"); 
       System.out.print("Country languages : "); 
       for(int j=0;j<languages.length();j++) 
       { 
        System.out.print(languages.get(j) +" "); 
       } 
       System.out.println(""); 
       String capital = jsonarray.getJSONObject(i).getString("capital"); 
       System.out.println("Country Capital : " + capital); 
      } 

      conn.disconnect(); 

      } 

      catch (MalformedURLException e) 
      { 
       e.printStackTrace(); 
      } 
      catch (IOException e) 
      { 
       e.printStackTrace(); 

      } 
    } 

}