用空标记解析SoapObject XML

问题描述：

大家好我解析从webservice Soaobject xml然后xml标记不为空有一切正常，但然后它们是空的示例“<barcode></barcode>”它使字符串anyType {}。并显示在我的列表中！ :(我该怎么办从列表中删除这个单词“anyType {}”，它没有显示任何东西或我写的东西？ envelope.implicitTypes = false; --->这不工作....仍然得到anyType {} ... 这是我的代码：用空标记解析SoapObject XML

String [] xmlElements = {“Id”，“name”，“Unit”，“Cost”，“description”，“barcode”};

SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); 
     envelope.dotNet=true; 
     envelope.setOutputSoapObject(request); 

     androidHttpTransport.call(SOAP_ACTION, envelope); 

     ArrayList<HashMap<String, String>> Tags = new ArrayList<HashMap<String, String>>(); 

     if (xmlelements==null&& KEY_RAKTINIS==null){ 
      Object soapObj = (SoapObject)envelope.getResponse(); 
      soapObj = ((SoapObject) soapObj).getProperty(KEY_PATVIRTINIMAS); 
     Toast.makeText(getActivity().getBaseContext(), soapObj.toString(), Toast.LENGTH_SHORT).show(); 

     }else { 
      SoapObject soapObj = (SoapObject)envelope.getResponse(); 
    soapObj = (SoapObject) soapObj.getProperty(KEY_RAKTINIS);// su situo ieinu i butent customers punkta 

     for (int j = 0; j < soapObj.getPropertyCount(); j++) { 
     SoapObject soapObjMenu = (SoapObject) soapObj.getProperty(j); 

    for (int i = 0; i <1; i++) { 
       HashMap<String, String> map = new HashMap<String, String>(); 
        for(i=0; i < xmlelements.length;i++){ 

      if (soapObjMenu.getProperty(xmlelements[i])!="") { 
       map.put(xmlelements[i], (soapObjMenu.getProperty(xmlelements[i]).toString())); 
       Log.v(xmlelements[i], "sitas");} 
       } 

        Tags.add(map); 
           }}

<Items>

<Item>

<Id>1000</Id>

<name>LCD Television HD Black 42 inches</name>

<Unit>ea</Unit>

<Cost>2000.00</Cost>

<description>Simple SKU</description>

<barcode></barcode>

</Item>

<Item>

<Id>1001</Id>

<name>LCD Television Model 01</name>

<Unit>ea</Unit>

<Cost>4015.00</Cost>

<description></description>

<barcode></barcode>

</Item>

<Item>

<Id>1003</Id>

<name>Plasma Television Model 01</name>

<Unit>ea</Unit>

<Cost>4020.00</Cost>

<description></description>

<barcode></barcode>

</Item>

答

我解决问题，只是用.equals（ “该字符串”）

例

HashMap<String, String> map = new HashMap<String, String>(); 
        for(i=0; i < xmlelements.length;i++){ 


         if (!soapObjMenu.getProperty(xmlelements[i]).toString().equals("anyType{}")){ // use when tag is empty... 
       map.put(xmlelements[i], (soapObjMenu.getProperty(xmlelements[i]).toString()));}else{ map.put(xmlelements[i], (" "));} 
          } 
        Tags.add(map); 
           }}}

附：如果你不会在字符串中使用空间，那么它就会成为问题，然后你在这张地图上将它发送到你的应用程序中。把（xmlelements [i]，（“”））因此必须改变它只是为了空间;）

没有人帮助，但我希望它有助于某人;）

用空标记解析SoapObject XML

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