如何在创建XMPPRoom时设置并获取roomName（组名）？

Question

我想创建XMPPRoom哪里无法设置房间名称，也收到节格式不包含房间名称，请帮我解决这个问题，在后端能够看到roomName。

这里是我的代码来创建xmppRoom。

func createGroupChat(){ 

    // membersToInvite = members 

    let xmppRoomMemoryStorage = XMPPRoomMemoryStorage() 

    let currentTimeMills = self.currentTimeMillis() 
    let createdBy = (appDelegate.xmppStream?.myJID.user)! as String 

    let jidString = String(format: "group%@_%@%@",currentTimeMills,createdBy,"@conference.hostname") 

    let xmppJid = XMPPJID(string: jidString) 
    let xmppRoom = XMPPRoom.init(roomStorage: xmppRoomMemoryStorage, jid: xmppJid) 


    xmppRoom?.activate(appDelegate.xmppStream) 
    xmppRoom?.addDelegate(self, delegateQueue: DispatchQueue.main) 
    xmppRoom?.join(usingNickname: appDelegate.xmppStream?.myJID.full(), history: nil) 

} 

func xmppRoomDidCreate(_ sender: XMPPRoom!) { 

    print(sender) 

} 


func xmppRoomDidJoin(_ sender: XMPPRoom!) { 

    sender.fetchConfigurationForm() 

    for JID in selectedParticipantsAry { 

     sender.editPrivileges([XMPPRoom.item(withAffiliation: "member", jid: XMPPJID(string: JID as! String))]) 

     sender.inviteUser(XMPPJID(string: JID as! String), withMessage: "THIS IS GROUP MESSAGE") 

    } 

} 


func xmppRoom(_ sender: XMPPRoom!, didFetchConfigurationForm configForm: DDXMLElement!) 
{ 

    let newConfig: DDXMLElement = configForm.copy() as! DDXMLElement 
    let fields = newConfig.elements(forName: "field") 

    for field in fields { 
     let vars = field.attribute(forName: "var") 
     // Make Room Persistent 
     if (vars?.stringValue == "muc#roomconfig_persistentroom") { 
      field.removeChild(at: 0) 
      field.addChild(DDXMLElement(name: "value", stringValue : "1")) 

     }else if (vars?.stringValue == "muc#roomconfig_roomname"){ 

      field.removeChild(at: 0) 
      field.addChild(DDXMLElement(name: "value", stringValue : "GroupNameString")) 
     } 
    } 

    sender.configureRoom(usingOptions: newConfig) 

} 

    func xmppStream(_ sender: XMPPStream!, didSend message: XMPPMessage!){ 

<message to="[email protected]"><x xmlns="http://jabber.org/protocol/muc#user"><invite to="[email protected]"> <reason>THIS IS GROUP MESSAGE</reason></invite></x></message> 

} 

func xmppStream(_ sender: XMPPStream!, didReceive message: XMPPMessage!){ 

    <message xmlns="jabber:client" from="group148057strong [email protected]" to="[email protected]/33932018081480575881630558" type="groupchat" id="75252205"><x xmlns="http://jabber.org/protocol/muc#user"><status code="104"></status></x> </message> 
} 

Answer 1

在代码中，有两种不同的Room Name：

1. groupxxx在

   字符串（格式为： “一群％@ _％@％@”，currentTimeMills，createdBy” @ conference.hostname“）

格式为[email protected]。

1. GroupNameString在配置表单中设置。

你在说什么？

对于＃1，这是在from节，你只需要从jid中取出。

对于＃2，它不会包含在节中，您必须要求提供房间信息。 http://xmpp.org/extensions/xep-0045.html#disco-roominfo