在php代码中插入jquery
如何将此代码放入我的程序中的注册码中,如果注册成功,将弹出?我与jquery新,所以我不知道如何做这个东西...请帮助我的人请。在php代码中插入jquery
<script>
$(document).ready(function() {
// show a dialog box when clicking on a link
$("#success").on('click', function(e) {
e.preventDefault();
$.Zebra_Dialog('<strong>Congratulations </strong>' +
'You are now successfully registered!');
});
});
</script>
这里是我的PHP代码:
<?php
if(isset($_POST['save'])) {
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$position = $_POST['position'];
$username = $_POST['username'];
$password = $_POST['password'];
$dateregistered = date("Y-m-d H:i:s");
if (!$_POST['fname'] || !$_POST['lname'] || !$_POST['position'] || !$_POST['username'] || !$_POST['password']) {
echo "You did not complete all of the required fields!";
} else {
$query="INSERT INTO users (position, fname, lname, username,password,dateregistered) VALUES ('$position','$fname','$lname','$username','$password',CURRENT_TIMESTAMP) ";
mysql_query($query);
if($query)
echo "You Successfully Created an Account!";
}
}
?>
我想更换回声事情到jQuery代码...任何人都知道如何???
附加jQuery的功能是你的PHP代码
<?php
if(isset($_POST['save']))
{
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$position = $_POST['position'];
$username = $_POST['username'];
$password = $_POST['password'];
$dateregistered = date("Y-m-d H:i:s");
if (!$_POST['fname'] || !$_POST['lname'] || !$_POST['position'] || !$_POST['username'] || !$_POST['password'])
{
echo "You did not complete all of the required fields!";
}
else
{
$query="INSERT INTO users (position, fname, lname, username,password,dateregistered) VALUES ('$position','$fname','$lname','$username','$password',CURRENT_TIMESTAMP) ";
mysql_query($query);
if($query){
echo "You Successfully Created an Account!";
// append here your jquery code
?>
<script>
$(document).ready(function() {
// show a dialog box when clicking on a link
$.Zebra_Dialog('<strong>Congratulations </strong>' +
'You are now successfully registered!');
});
</script>
<?php
}
}
}
//corrected indentation
?>
您的缩进是可怕的人! – pythonian29033
@ pythonian29033感谢兄弟 –
没问题的人,下次再检查一下,我打算给出这个答案,但你是第一个 – pythonian29033
您可以简单地使用
echo "<script>alert('You Successfully Created an Account!')</script>";
尝试做这样的:
if($query)
{
?>
<script>
$(document).ready(function() {
$.Zebra_Dialog('<strong>Congratulations </strong>' +
'You are now successfully registered!');
});
</script>
<?php
}
**Try this code.......**
<?php
if(isset($_POST['save']))
{
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$position = $_POST['position'];
$username = $_POST['username'];
$password = $_POST['password'];
$dateregistered = date("Y-m-d H:i:s");
if (!$_POST['fname'] || !$_POST['lname'] || !$_POST['position'] || !$_POST['username'] || !$_POST['password'])
{
echo "<script>
$(document).ready(function() {
$('#success').on('click', function(e) {
e.preventDefault();
$.Zebra_Dialog('<strong>Congratulations </strong>' +
'You did not complete all of the required fields!');
});
});
</script>";
}
else
{
$query="INSERT INTO users (position, fname, lname, username,password,dateregistered) VALUES ('$position','$fname','$lname','$username','$password',CURRENT_TIMESTAMP) ";
if(mysql_query($query)){
echo "<script>
$(document).ready(function() {
$('#success').on('click', function(e) {
e.preventDefault();
$.Zebra_Dialog('<strong>Congratulations </strong>' +
'You Successfully Created an Account!');
});
});
</script>";
}
}
}
?>
好,最简单的解决办法是要回显jQuery代码。 –
@YUNOWORK除了几乎是唯一的解决方案... – Ryan
好吧,用PHP向DOM添加代码并不能提供太多的可能性^^我想你可以使用DOMDocument,但是这太多努力只为一个小文本框。 –