Powershell - 您如何解析内容:从RSS提要(XML)编码?
问题描述:
我试图从使用PowerShell的RSS源解析出数据。Powershell - 您如何解析内容:从RSS提要(XML)编码?
如何获取标题,guid和内容:编码字段的内容?
由于某种原因,我下面的代码只是返回“...”。
任何帮助非常感谢!
[xml]$hsg = Invoke-WebRequest http://technet.microsoft.com/en-us/security/rss/comprehensive
#$hsg.rss.channel.item | select title #this prints the list of blog posts
$ContentNamespace = New-Object Xml.XmlNamespaceManager $hsg.NameTable
$ContentNamespace.AddNamespace("content", "http://purl.org/rss/1.0/modules/content/")
#$hsg.rss.channel.item #this prints the list of posts
$hsg.rss.channel.item.selectSingleNode("content:encoded", $ContentNamespace)
的数据是这样的:
<rss xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:rssdatehelper="urn:rssdatehelper" version="2.0">
<channel>
<title>Microsoft Security Content: Comprehensive Edition</title>
<link>http://technet.microsoft.com/security/bulletin</link>
<dc:date>Wed, 15 May 2013 08:00:00 GMT</dc:date>
<generator>umbraco</generator>
<description>Microsoft Security Content: Comprehensive Edition</description>
<language>en-US</language>
<item>
<title>
MS13-045 - Important : Vulnerability in Windows Essentials Could Allow Information Disclosure (2813707) - Version: 1.1
</title>
<link>
http://technet.microsoft.com/en-us/security/bulletin/ms13-045
</link>
<dc:date>2013-05-15T07:00:00.0000000Z</dc:date>
<guid>
http://technet.microsoft.com/en-us/security/bulletin/ms13-045
</guid>
<content:encoded>
<![CDATA[
Severity Rating: Important<br />
Revision Note: V1.1 (May 15, 2013): Corrected link to the download location in the Detection and Deployment Tools and Guidance section. This is an informational change only.<br />
Summary: This security update resolves a privately reported vulnerability in Windows Writer. The vulnerability could allow information disclosure if a user opens Writer using a specially crafted URL. An attacker who successfully exploited the vulnerability could override Windows Writer proxy settings and overwrite files accessible to the user on the target system. In a web-based attack scenario, a website could contain a specially crafted link that is used to exploit this vulnerability. An attacker would have to convince users to visit the website and open the specially crafted link.
]]>
</content:encoded>
</item>
谢谢!
答
试试这个:解析数据的
$rss = [xml](Get-Content .\test.rss)
$rss.SelectNodes('//item') | % {
$posts += New-Object psobject -Property @{
Title = $_.Title.Trim()
Guid = $_.Guid.Trim()
Content = $_.Encoded."#cdata-section".Trim()
}
}
样品(数组只包含一个项目,因为那里不仅是一个你的样品中):
$posts
Title Guid Content
----- ---- -------
MS13-045 - Important : Vulnera... http://technet.microsoft.com/... Severity Rating: Important<br...
顺便说一句,你的样品缺乏在以下结尾:
</channel>
</rss>
答
您可以绕过将输出写入中间文件,跳过获取内容。弗罗德把它很好地包装成了一个提供解决方案的psobject。
cls
$x=[xml](iwr 'https://technet.microsoft.com/en-us/security/rss/comprehensive').content
foreach ($y in $x.rss.channel.selectnodes('//item')) {
"`r`n`t$($y.title)"
$y.pubdate
$y.link
$y.encoded.'#cdata-section'
}
你可能会发现你的RSS/ATOM返回一个略微不同的结构,我发现这个必要针对不同的饲料:
foreach ($y in $x.feed.entry)
IDE中的智能感知帮助我导航。
这样做!谢谢,@Graimer! – mbourgon