如何将十六进制值转换为NSString？

问题描述：

我为十六进制值转换为相应的NSString，但下面的代码它不是为我工作如何将十六进制值转换为NSString？

NSMutableString * newString = [[NSMutableString alloc] init]; 
NSString *[email protected]"5c 57 c7 25 d9 57 b9 4c"; 
NSScanner *scanner = [[NSScanner alloc] initWithString:string]; 
unsigned value; 
while([scanner scanHexInt:&value]) { 
    [newString appendFormat:@"%c",(char)(value & 0xFF)]; 
} 
string = [newString copy]; 
NSLog(@"%@",string);

请帮我

答

一次尝试这样的，

- (NSString *) stringFromHex:(NSString *)str 
{ 
    NSMutableData *stringData = [[NSMutableData alloc] init] ; 
    unsigned char whole_byte; 
    char byte_chars[3] = {'\0','\0','\0'}; 
    int i; 
    for (i=0; i < [str length]/2; i++) { 
     byte_chars[0] = [str characterAtIndex:i*2]; 
     byte_chars[1] = [str characterAtIndex:i*2+1]; 
     whole_byte = strtol(byte_chars, NULL, 16); 
     [stringData appendBytes:&whole_byte length:1]; 
    } 

    return [[NSString alloc] initWithData:stringData encoding:NSASCIIStringEncoding] ; 
}

调用这个样子，

NSString* string = [self stringFromHex:@"5c 57 c7 25 d9 57 b9 4c"]; 
NSLog(@"%@",string);

答

需要试试这个当我尝试这样做。

NSString * str = @"68656C6C6F"; 
NSMutableString * newString = [[[NSMutableString alloc] init] autorelease]; 
int i = 0; 
while (i < [str length]) 
{ 
    NSString * hexChar = [str substringWithRange: NSMakeRange(i, 2)]; 
    int value = 0; 
    sscanf([hexChar cStringUsingEncoding:NSASCIIStringEncoding], "%x", &value); 
    [newString appendFormat:@"%c", (char)value]; 
    i+=2; 
}

答

你可以使用这个转换为：

NSString *[email protected]"5c 57 c7 25 d9 57 b9 4c"; 
NSMutableString * newString = [NSMutableString string]; 

NSArray * components = [str componentsSeparatedByString:@" "]; 
for (NSString * component in components) { 
    int value = 0; 
    sscanf([component cStringUsingEncoding:NSASCIIStringEncoding], "%x", &value); 
    [newString appendFormat:@"%c", (char)value]; 
} 

NSLog(@"%@", newString);

希望它可以帮助你。

如何将十六进制值转换为NSString？

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