如何将目标c的完成块转换为Swift?
问题描述:
我在迅速的新尝试客观C座语法转换迅速的Xcode 6.3.2如何将目标c的完成块转换为Swift?
完成块的typedef:
typealias CompletionWithBoolBlock = (Bool, NSError, NSString) -> Void
[Model insertObjectWithTable:@"tblStudent" values:dict completion:^(BOOL success, NSError *responseError, NSString *object){
if(success){
NSLog(@"inserted");
}
else
{
NSLog(@"Not inserted, %@",responseError.description);
}
}];
冲浪净后,我试着用
Model.insertObjectWithTable("tblStudent", values: dict, completion:({(success:Bool,responseError:NSError, object:NSString)->(Void) in
if success
{
println("inserted")
}
else
{
println("Not inserted \(responseError.description)")
}
})
}
和
Model.insertObjectWithTable("tblStudent", values: dict, completion:(success:Bool,responseError:NSError, object:NSString)->Void{
if success
{
println("inserted")
}
else
{
println("Not inserted \(responseError.description)")
}
})
但它显示我错误
预计 '' 分隔符
在表达式列表预计表达
答
你试过
Model.insertObjectWithTable("tblStudent", values: dict, completion:{(success:Bool, responseError:NSError, object:NSString) -> Void in
if success {
println("inserted")
} else {
println("Not inserted \(responseError.description)")
}
})