为每一个元素迭代时添加一个延迟

Question

尝试使用SKLabelNode在标签上逐个显示下面数组中的元素。我认为问题在于它比数组更快地遍历数组，因此导致崩溃，因为self.addChild()尝试再次显示“Set”，而“Ready”仍在显示。

我的问题是，我如何减慢这个迭代，以便在“Set”显示之前“Ready”可以出现和消失？

let readySetGo = ["Ready", "Set", "GO!"] 
for i in readySetGo { 
    newLevelLabel.text = i 
    newLevelLabel.fontSize = 60 

    let wait = SKAction.wait(forDuration: 2) 
    let remove = SKAction.removeFromParent() 
    let sequence = SKAction.sequence([wait, remove]) 

    newLevelLabel.run(sequence) 

    self.addChild(newLevelLabel) 
} 

Answer 1

它之所以被立即会去是因为你不链条一切行动以相同的顺序，那么你所有的阶段都在同一时间运行：

试试这个，我现在不是编译器：

let readySetGo = ["Ready", "Set", "GO!"] 

newLevelLabel.fontSize = 60 

let seq: [SKAction]=[] 
let waitTime:TimeIneterval = 2 

for i in readySetGo { 

    let block = SKAction.run{ 
     self.newLevelLabel.text = i 
    } 

    let wait = SKAction.wait(forDuration: waitTime) 

    seq.append(wait) 
    seq.append(block) 

} 

let wait = SKAction.wait(forDuration: waitTime) 
let remove = SKAction.removeFromParent() 
seq.append(wait) 
seq.append(remove) 
let sequence = SKAction.sequence(seq) 

newLevelLabel.run(sequence) 

self.addChild(newLevelLabel)