如何在Swift中点击按钮打开Whatsapp或其他iOS应用程序？

Question

我想从app_A打开一个iOS app_B，然后想要将app_B的数据放回到app_A中，在下面尝试打开whatsapp，但没有奏效。请帮助如何在iOS中实现这一点，在此先感谢。

@IBAction func clickMe(_ sender: UIButton) { 

     let url = "https://api.whatsapp.com/send?00919599****** " 
     let whatUpUrl = NSURL(string: url) 
     if UIApplication.shared.canOpenURL(whatUpUrl! as URL){ 
      UIApplication.shared.openURL(whatUpUrl! as URL) 
     } else { 
      //redirect to safari because the user doesn't have Whatsapp installed 
      UIApplication.shared.openURL(NSURL(string: "http://whatsapp.com/")! as URL) 
     } 
    } 

Answer 1

WEBURL链接打开聊天

let whatsappURL = URL(string: "https://api.whatsapp.com/send?phone=9512347895&text=Invitation") 
    if UIApplication.shared.canOpenURL(whatsappURL!) { 
     UIApplication.shared.openURL(whatsappURL!) 
    } 

注：在info.plist中

<key>LSApplicationQueriesSchemes</key> 
<array> 
    <string>whatsapp</string> 
</array> 

Answer 2

添加URL方案添加这Info.plist中

然后在你想打开whatsapp的按钮上使用这个。

@IBAction func whatsappButtonPressed(_ sender: Any) { 
     var str = "Hello to whatsapp" 
     str = str.addingPercentEncoding(withAllowedCharacters: (NSCharacterSet.urlQueryAllowed))! 
     let whatsappURL = NSURL(string: "whatsapp://send?text=\(str)") 

     if UIApplication.shared.canOpenURL(whatsappURL! as URL) { 
      UIApplication.shared.openURL(whatsappURL! as URL) 
     } else { 
      showAlert(message: "Whatsapp is not installed on this device. Please install Whatsapp and try again.") 
     } 
} 

同样，对于其他应用： 替换 - NSURL（字符串： “WhatsApp的：//发送文本=（STR）？”）与 NSURL（字符串： “APPNAME：//”）。 您还需要将该应用程序添加到Info.plist，如上所述。

谢谢！