通过python脚本截图。 [Linux]
此工程无需使用scrot或ImageMagick。
import gtk.gdk
w = gtk.gdk.get_default_root_window()
sz = w.get_size()
print "The size of the window is %d x %d" % sz
pb = gtk.gdk.Pixbuf(gtk.gdk.COLORSPACE_RGB,False,8,sz[0],sz[1])
pb = pb.get_from_drawable(w,w.get_colormap(),0,0,0,0,sz[0],sz[1])
if (pb != None):
pb.save("screenshot.png","png")
print "Screenshot saved to screenshot.png."
else:
print "Unable to get the screenshot."
使用wxPythonhttp://ubuntuforums.org/showpost.php?p=2681009&postcount=5
import ImageGrab
img = ImageGrab.grab()
img.save('test.jpg','JPEG')
这需要Python图像库
只适用于Windows:http://www.pythonware.com/library/ pil/handbook/imagegrab.htm – bernie 2009-04-04 19:52:12
这一个适用于X11,也许在Windows太(某人,请检查)。 Needs PyQt4:
import sys
from PyQt4.QtGui import QPixmap, QApplication
app = QApplication(sys.argv)
QPixmap.grabWindow(QApplication.desktop().winId()).save('test.png', 'png')
请注意PyQt的许可,它比Python和Qt更具限制性。 http://www.riverbankcomputing.co.uk/software/pyqt/license – user120242 2009-08-13 05:09:19
用户kmilin(以下)报告说,这在Windows上工作 – 2009-12-03 15:07:29
这是唯一的解决方案,可以在我的Linux安装上“开箱即用” 。我不知道为什么,但我到处都有PyQt4,而缺乏PyWX,PyGtk,ImageGrab。 - 谢谢 :)。 – 2012-02-03 19:17:53
跨平台解决方案,借:
import wx
wx.App() # Need to create an App instance before doing anything
screen = wx.ScreenDC()
size = screen.GetSize()
bmp = wx.EmptyBitmap(size[0], size[1])
mem = wx.MemoryDC(bmp)
mem.Blit(0, 0, size[0], size[1], screen, 0, 0)
del mem # Release bitmap
bmp.SaveFile('screenshot.png', wx.BITMAP_TYPE_PNG)
编译所有的答案中的一类。 输出PIL图像。
#!/usr/bin/env python
# encoding: utf-8
"""
screengrab.py
Created by Alex Snet on 2011-10-10.
Copyright (c) 2011 CodeTeam. All rights reserved.
"""
import sys
import os
import Image
class screengrab:
def __init__(self):
try:
import gtk
except ImportError:
pass
else:
self.screen = self.getScreenByGtk
try:
import PyQt4
except ImportError:
pass
else:
self.screen = self.getScreenByQt
try:
import wx
except ImportError:
pass
else:
self.screen = self.getScreenByWx
try:
import ImageGrab
except ImportError:
pass
else:
self.screen = self.getScreenByPIL
def getScreenByGtk(self):
import gtk.gdk
w = gtk.gdk.get_default_root_window()
sz = w.get_size()
pb = gtk.gdk.Pixbuf(gtk.gdk.COLORSPACE_RGB,False,8,sz[0],sz[1])
pb = pb.get_from_drawable(w,w.get_colormap(),0,0,0,0,sz[0],sz[1])
if pb is None:
return False
else:
width,height = pb.get_width(),pb.get_height()
return Image.fromstring("RGB",(width,height),pb.get_pixels())
def getScreenByQt(self):
from PyQt4.QtGui import QPixmap, QApplication
from PyQt4.Qt import QBuffer, QIODevice
import StringIO
app = QApplication(sys.argv)
buffer = QBuffer()
buffer.open(QIODevice.ReadWrite)
QPixmap.grabWindow(QApplication.desktop().winId()).save(buffer, 'png')
strio = StringIO.StringIO()
strio.write(buffer.data())
buffer.close()
del app
strio.seek(0)
return Image.open(strio)
def getScreenByPIL(self):
import ImageGrab
img = ImageGrab.grab()
return img
def getScreenByWx(self):
import wx
wx.App() # Need to create an App instance before doing anything
screen = wx.ScreenDC()
size = screen.GetSize()
bmp = wx.EmptyBitmap(size[0], size[1])
mem = wx.MemoryDC(bmp)
mem.Blit(0, 0, size[0], size[1], screen, 0, 0)
del mem # Release bitmap
#bmp.SaveFile('screenshot.png', wx.BITMAP_TYPE_PNG)
myWxImage = wx.ImageFromBitmap(myBitmap)
PilImage = Image.new('RGB', (myWxImage.GetWidth(), myWxImage.GetHeight()))
PilImage.fromstring(myWxImage.GetData())
return PilImage
if __name__ == '__main__':
s = screengrab()
screen = s.screen()
screen.show()
我有scrot,ImageMagick的,PyQt的,WX和PyGTK的一个包装项目(pyscreenshot)。 如果你有其中一个,你可以使用它。 本讨论包含所有解决方案。
安装:
easy_install pyscreenshot
例子:
import pyscreenshot as ImageGrab
# fullscreen
im=ImageGrab.grab()
im.show()
# part of the screen
im=ImageGrab.grab(bbox=(10,10,500,500))
im.show()
# to file
ImageGrab.grab_to_file('im.png')
只是为了完整性: Xlib的 - 但捕捉整个屏幕时,它的有些慢:
from Xlib import display, X
import Image #PIL
W,H = 200,200
dsp = display.Display()
root = dsp.screen().root
raw = root.get_image(0, 0, W,H, X.ZPixmap, 0xffffffff)
image = Image.fromstring("RGB", (W, H), raw.data, "raw", "BGRX")
image.show()
人们可以尝试在PyXlib的瓶颈文件中放入一些类型,然后使用Cython进行编译。这可能会提高速度。
编辑: 我们可以写在C函数的核心,然后从ctypes的Python中使用它,这里是我砍死在一起:
#include <stdio.h>
#include <X11/X.h>
#include <X11/Xlib.h>
//Compile hint: gcc -shared -O3 -lX11 -fPIC -Wl,-soname,prtscn -o prtscn.so prtscn.c
void getScreen(const int, const int, const int, const int, unsigned char *);
void getScreen(const int xx,const int yy,const int W, const int H, /*out*/ unsigned char * data)
{
Display *display = XOpenDisplay(NULL);
Window root = DefaultRootWindow(display);
XImage *image = XGetImage(display,root, xx,yy, W,H, AllPlanes, ZPixmap);
unsigned long red_mask = image->red_mask;
unsigned long green_mask = image->green_mask;
unsigned long blue_mask = image->blue_mask;
int x, y;
int ii = 0;
for (y = 0; y < H; y++) {
for (x = 0; x < W; x++) {
unsigned long pixel = XGetPixel(image,x,y);
unsigned char blue = (pixel & blue_mask);
unsigned char green = (pixel & green_mask) >> 8;
unsigned char red = (pixel & red_mask) >> 16;
data[ii + 2] = blue;
data[ii + 1] = green;
data[ii + 0] = red;
ii += 3;
}
}
XDestroyImage(image);
XDestroyWindow(display, root);
XCloseDisplay(display);
}
然后蟒蛇-file:
import ctypes
import os
from PIL import Image
LibName = 'prtscn.so'
AbsLibPath = os.path.dirname(os.path.abspath(__file__)) + os.path.sep + LibName
grab = ctypes.CDLL(AbsLibPath)
def grab_screen(x1,y1,x2,y2):
w, h = x2-x1, y2-y1
size = w * h
objlength = size * 3
grab.getScreen.argtypes = []
result = (ctypes.c_ubyte*objlength)()
grab.getScreen(x1,y1, w, h, result)
return Image.frombuffer('RGB', (w, h), result, 'raw', 'RGB', 0, 1)
if __name__ == '__main__':
im = grab_screen(0,0,1440,900)
im.show()
试试:
#!/usr/bin/python
import gtk.gdk
import time
import random
import socket
import fcntl
import struct
import getpass
import os
import paramiko
while 1:
# generate a random time between 120 and 300 sec
random_time = random.randrange(20,25)
# wait between 120 and 300 seconds (or between 2 and 5 minutes)
print "Next picture in: %.2f minutes" % (float(random_time)/60)
time.sleep(random_time)
w = gtk.gdk.get_default_root_window()
sz = w.get_size()
print "The size of the window is %d x %d" % sz
pb = gtk.gdk.Pixbuf(gtk.gdk.COLORSPACE_RGB,False,8,sz[0],sz[1])
pb = pb.get_from_drawable(w,w.get_colormap(),0,0,0,0,sz[0],sz[1])
ts = time.asctime(time.localtime(time.time()))
date = time.strftime("%d-%m-%Y")
timer = time.strftime("%I:%M:%S%p")
filename = timer
filename += ".png"
if (pb != None):
username = getpass.getuser() #Get username
newpath = r'screenshots/'+username+'/'+date #screenshot save path
if not os.path.exists(newpath): os.makedirs(newpath)
saveas = os.path.join(newpath,filename)
print saveas
pb.save(saveas,"png")
else:
print "Unable to get the screenshot."
这是一个古老的问题。我想用新工具回答它。
适用于python 3(应该使用python 2,但我没有测试过)和PyQt5。
最小工作示例。将它复制到python shell并获得结果。
from PyQt5.QtWidgets import QApplication
app = QApplication([])
screen = app.primaryScreen()
screenshot = screen.grabWindow(QApplication.desktop().winId())
screenshot.save('/tmp/screenshot.png')
有点晚了,但没关系容易的是
import autopy
import time
time.sleep(2)
b = autopy.bitmap.capture_screen()
b.save("C:/Users/mak/Desktop/m.png")
我不能把屏幕截图的Linux与pyscreenshot或scrot因为pyscreenshot
输出只是一个黑屏png图像文件。
但感谢上帝,还有另一种非常简单的方式在Linux中进行截图,而无需安装任何东西。只要把下面的代码在你的目录,并与python demo.py
import os
os.system("gnome-screenshot --file=this_directory.png")
运行也有许多可用的选项gnome-screenshot --help
Application Options:
-c, --clipboard Send the grab directly to the clipboard
-w, --window Grab a window instead of the entire screen
-a, --area Grab an area of the screen instead of the entire screen
-b, --include-border Include the window border with the screenshot
-B, --remove-border Remove the window border from the screenshot
-p, --include-pointer Include the pointer with the screenshot
-d, --delay=seconds Take screenshot after specified delay [in seconds]
-e, --border-effect=effect Effect to add to the border (shadow, border, vintage or none)
-i, --interactive Interactively set options
-f, --file=filename Save screenshot directly to this file
--version Print version information and exit
--display=DISPLAY X display to use
不能使用[scrot(HTTP任何理由://linux.die .NET /人/ 1/scrot)? – Mark 2009-04-20 10:46:48
我很想查看下面的建议方法的性能。 – JDong 2014-07-01 17:01:57
@Mark - 无效链接。 – ArtOfWarfare 2015-08-01 13:18:56