如何当用户触摸屏幕时

Question

我设计其中包括图像的应用程序在一个特定的区域播放声音...

我将尝试使用下面的代码来播放声音...

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event 
{ 

UITouch *touch = [touches anyObject]; 


CGPoint point = [touch locationInView:self.view]; 
if (CGRectContainsPoint(CGRectMake(320,480,0,0),point));//CGRectMake(5, 5, 40, 130), point)) 
{ 
    AVAudioPlayer *player; 
    if(!player){ 

     NSString* resourcePath = [[NSBundle mainBundle] resourcePath]; 
     resourcePath = [resourcePath stringByAppendingString:@"/try.wav"]; 
     NSLog(@"Path to play: %@", resourcePath); 
     NSError* err; 

     //Initialize our player pointing to the path to our resource 
     player = [[AVAudioPlayer alloc] initWithContentsOfURL: 
        [NSURL fileURLWithPath:resourcePath] error:&err]; 

     if(err){ 
      //bail! 
      NSLog(@"Failed with reason: %@", [err localizedDescription]); 
     } 
     else{ 
      //set our delegate and begin playback 
      player.delegate = self; 
      [player play]; 
     } 
    } 

} 
} 

在上面的代码中，当在屏幕上的任何位置检测到触摸时，声音播放。当用户触摸屏幕上的不同位置时，我想播放5种不同的声音（例如，当用户触摸宽度100-200和高度50-100时，1.wav）。任何人都可以请帮助我如何设置半径，并在指定半径内触摸时发出不同的声音...

Answer 1

CGRect area1 = CGRectMake(10,10, 10, 10); 
CGRect area2 = CGRectMake(100,10, 10, 10); 
CGRect area3 = CGRectMake(10,100, 10, 10); 
CGRect area4 = CGRectMake(100,100, 10, 10); 

if (CGRectContainsPoint(area1, point)) { 
// play sound 1 
} else ... 
......