使用字符串缩进和换行连续匹配行

Question

我想将包含代码片段的可预测格式的文件转换为Markdown。文件看起来像这样：

MY CODE SNIPPETS   2015-05-01 

This file contains useful code snippets for every day usage 
in the Linux command line. 

SED 
    sed 's/\(.*\)1/\12/g'     # Modify anystring1 to anystring2 
    sed '/^ *#/d; /^ *$/d'     # Remove comments and blank lines 

SORT 
    sort -t. -k1,1n -k2,2n -k3,3n -k4,4n # Sort IPV4 ip addresses 

... 

线开始sed或sort（小写 - 可具有在前面的空格）应与```包裹（降价起始/结束码的标记）中，用4个空格缩进和具有1该部分之前和之后的空行。连续行sed或sort应包装在相同的编码部分。最终的降价文件应该是这样的：

MY CODE SNIPPETS   2015-05-01 

This file contains useful code snippets for every day usage 
in the Linux command line. 

SED 

    ``` 
    sed 's/\(.*\)1/\12/g'     # Modify anystring1 to anystring2 
    sed '/^ *#/d; /^ *$/d'     # Remove comments and blank lines 
    ``` 

SORT 

    ``` 
    sort -t. -k1,1n -k2,2n -k3,3n -k4,4n # Sort IPV4 ip addresses 
    ``` 

我会在awk/sed/bash解决方案最感兴趣，但其他建议将会受到欢迎。

Answer 1

也许是这样的：

awk ' 
    $1 ~ /^(sed|sort)$/ { 
     print "\n ```" 
     while ($1 ~ /^(sed|sort)$/) { 
      sub(/^[ \t]*/, " ") 
      print 
      if (!getline) { 
       print " ```\n" 
       exit 
      } 
     } 
     print " ```\n" 
    } 
    1' 

输出：

MY CODE SNIPPETS   2015-05-01 

This file contains useful code snippets for every day usage 
in the Linux command line. 

SED 

    ``` 
    sed 's/\(.*\)1/\12/g'     # Modify anystring1 to anystring2 
    sed '/^ *#/d; /^ *$/d'     # Remove comments and blank lines 
    ``` 


SORT 

    ``` 
    sort -t. -k1,1n -k2,2n -k3,3n -k4,4n # Sort IPV4 ip addresses 
    ``` 

Answer 2

另一个awk变体：
（逻辑非常类似于其他回答）

awk ' 
    BEGIN{p=0} 
    /^ *(sed|sort)/{ 
     if(!p)print "```"; 
     p=1; 
     print " " $0; 
     next 
     } 
    p{ 
     print "```" 
     p=0 
    } 
    1; 
    END{ 
     if(p)print "```" 
     }' my_commands.txt 

输出：

MY CODE SNIPPETS   2015-05-01 

This file contains useful code snippets for every day usage 
in the Linux command line. 

SED 
``` 
     sed 's/\(.*\)1/\12/g'     # Modify anystring1 to anystring2 
     sed '/^ *#/d; /^ *$/d'     # Remove comments and blank lines 
``` 

SORT 
``` 
     sort -t. -k1,1n -k2,2n -k3,3n -k4,4n # Sort IPV4 ip addresses 
```