如何通过一个数组在php循环数组内
问题描述:
这里的阵列结构(只有数组中的第一个元素):如何通过一个数组在php循环数组内
Array
(
[1] => Array
(
[pageid] => 1
[step_order] => 1
[pageurl] => http://www.domain.com/
[in_links] => Array
(
[domains] => Array
(
[Direct Entry] => 1520
[www.google.com] => 387
[www.google.co.in] => 14
[search.yahoo.com] => 10
[All other] => 27
)
[impressions] => Array
(
[Direct Entry] => Array
(
[0] => 10654
[1] => 10728
[2] => 10772
)
[www.google.com] => Array
(
[0] => 10991
[1] => 12455
[2] => 12466
[3] => 10757
)
[www.google.co.in] => Array
(
[0] => 9839
[1] => 9837
[2] => 9845
)
[search.yahoo.com] => Array
(
[0] => 12087
[1] => 10864
)
)
)
[out_links] => Array
(
[domain] => Array
(
[Left site] => 1752
[http://www.domain.com/#] => 102
[http://www.domain.com/contact] => 102
[http://www.domain.com/#basic_inline_div] => 2
)
[impressions] => Array
(
[Left site] => Array
(
[0] => 7680
[1] => 9728
[2] => 10496
)
[http://www.domain.com/#] => Array
(
[0] => 259
[1] => 11013
)
[http://www.domain.com/contact] => Array
(
[0] => 12802
[1] => 10757
)
[http://www.domain.com/#basic_inline_div] => Array
(
[0] => 11
[1] => 51
)
)
)
[visitors] => 1958
)
)
我试图循环等待来自域,印象中的元素(和子元素)。我设法得到了第一部分:pageid,step_order,page_url。我在in_links和out_links及其子数组中遇到了问题。任何人都有关于如何提取这些数据的想法?
答
以下是您如何从in_links获取域名的方法。其他类似(但我不确定印象子数组中的索引代表什么)。
foreach ($array as $element) {
foreach ($element['in_links']['domains'] as $domain => $count) {
echo "Domain: $domain, Count: $count\n";
}
}
这没有奏效。你确定你可以做'$ element ['in_links'] ['domains']'? – user962449 2013-03-14 17:48:49
是的,我很确定。我一直在做这样的嵌套关联数组访问。 – Barmar 2013-03-14 17:52:58