React Redux无法让Reducer拾取动作
问题描述:
我一直在学习REDX &反应,并正在建立todo列表。我一直在阅读和查看不同的文章,但无法弄清楚我在设置中缺少的东西。React Redux无法让Reducer拾取动作
当前,您可以通过输入添加待办事项。在推送输入它发送一个addTodo
行动与待办事项文本。
我期待reducer查看动作类型和更新状态,但它从来没有。我错过了什么?
index.jsx
import React from 'react';
import ReactDOM from 'react-dom';
import { createStore } from 'redux';
import { Provider } from 'react-redux';
import reducer from './reducer.js';
import TodoList from './containers/container.js';
const store = createStore(reducer);
ReactDOM.render(
<Provider store={store}>
<TodoList />
</Provider>,
document.getElementById('app'));
actions.js
var uuid = require('node-uuid');
export function addTodo(text) {
console.log('action addTodo', text);
return {
type: 'ADD_TODO',
payload: {
id: uuid.v4(),
text: text
}
};
}
TodoListComponent.jsx
import React from 'react';
import TodoComponent from './TodoComponent.jsx';
import { addTodo } from '../actions/actions.js'
export default class TodoList extends React.Component {
render() {
const { todos } = this.props;
return (
<div>
<input type='text' placeholder='Add todo' onKeyDown={this.onSubmit} />
<ul>
{todos.map(c => (
<li key={t.id}>
<TodoComponent todo={t} styleName='large' />
</li>
))}
</ul>
</div>
)
}
onSubmit(e) {
const input = e.target;
const text = input.value;
const isEnterKey = (e.which === 13);
if (isEnterKey) {
input.value = '';
addTodo(text);
}
}
}
TodoComponent.jsx
import React from 'react';
import CSSModules from 'react-css-modules';
import styles from './style.css';
export default class TodoComponent extends React.Component {
render() {
const { todo } = this.props;
return (
<div styleName='large'>{todo.text}</div>
)
}
}
export default CSSModules(TodoComponent, styles);
container.js
import { connect } from 'react-redux';
import TodoList from '../components/TodoListComponent.jsx';
import { addTodo } from '../actions/actions.js';
const mapStateToProps = (state) => {
return {
todos: state
}
};
const mapDispatchToProps = (dispatch) => {
return {
addTodo: text => dispatch(addTodo(text))
}
};
export default connect(mapStateToProps, mapDispatchToProps)(TodoList);
reducer.js
import { List, Map } from 'immutable';
const init = List([]);
export default function(todos = init, action) {
console.log('reducer action type', action.type);
switch(action.type) {
case 'ADD_TODO':
console.log('ADD_TODO');
return todos.push(Map(action.payload));
default:
return todos;
}
}
答
在你TodoListComponent
你直接导入你的行动从你的行动文件,但实际上你想要使用你的行动将其作为容器中的财产分派并传递。这就解释了为什么您会看到来自操作的日志,但不会看到来自Reducer的日志,因为该操作从未分派到商店。
所以你TodoListComponent
应该是:
import React from 'react';
import TodoComponent from './TodoComponent.jsx';
export default class TodoList extends React.Component {
render() {
const { todos } = this.props;
return (
<div>
<input type='text' placeholder='Add todo' onKeyDown={this.onSubmit} />
<ul>
{todos.map(c => (
<li key={t.id}>
<TodoComponent todo={t} styleName='large' />
</li>
))}
</ul>
</div>
)
}
onSubmit(e) {
const input = e.target;
const text = input.value;
const isEnterKey = (e.which === 13);
if (isEnterKey) {
input.value = '';
this.props.addTodo(text);
}
}
}
+0
感谢您的解释,是有道理的。这有效,你的答案缺少@opheman回答中提出的'onKeyDown = {this.onSubmit.bind(this)}'。 – Allanp
答
import React from 'react';
import TodoComponent from './TodoComponent.jsx';
export default class TodoList extends React.Component {
render() {
const { todos } = this.props;
return (
<div>
<input type='text' placeholder='Add todo' onKeyDown={this.onSubmit.bind(this)} />
<ul>
{todos.map(c => (
<li key={t.id}>
<TodoComponent todo={t} styleName='large' />
</li>
))}
</ul>
</div>
)
}
onSubmit(e) {
// use the addTodo passed via connect
const { addTodo } = this.props;
const input = e.target;
const text = input.value;
const isEnterKey = (e.which === 13);
if (isEnterKey) {
input.value = '';
addTodo(text);
}
}
}
在'TodoListComponent.jsx',你应该使用'props'通过'通过'addTodo' connect' – topheman
作为一个方面说明的答案下面,在Redux中工作时,你的reducer应该总是返回一个新的状态实例,而不是操作当前状态,而不是'return todos.push(Map(action.payload));'改变你应该使用的当前数组'返回todos.concat(Map(action.payload));'这将从当前状态和动作有效载荷中返回一个新数组。 –