创建视图?
问题描述:
目前我已经联接多个表一起一看,表设置以下列方式:创建视图?
ACCOUNTS (id, first_name, last_name, etc.)
CONTACTS (id, name, etc.)
ACCOUNT_CONTACTS (id, account_id, contact_id)
EMAIL_ADDR_BEAN_REL (id, bean_id (same as account_id/contact_id), email_address_id)
EMAIL_ADDRESSES (email_address_id, email_address)
但是我有两个表我一起加入这可以有一个ID相关联的多封邮件,在这里是结构的一个例子:
表:EMAIL_ADDR_BEAN_REL
id email_address_id bean_id
1 2d5b8 61720
2 14355b 61720
表:EMAIL_ADDRESSES
id email_address
2db58 [email protected]
14355b [email protected]
创建我的视图时,我希望能够检索这些与一个用户关联的多个电子邮件。目前,这是我认为的代码,只检索一个电子邮件:
SELECT AC.id, A.id AS account_id, A.name, A.description, A.industry, A.phone_fax, A.phone_office, A.shipping_address_street, A.shipping_address_city, A.shipping_address_state, A.shipping_address_postalcode, A.shipping_address_country, C.id AS contact_id, C.first_name, C.last_name, C.title, C.department, C.phone_home, C.phone_mobile, C.phone_work, C.primary_address_street, C.primary_address_city, C.primary_address_state, C.primary_address_postalcode, C.primary_address_country, EA.email_address, EA_C.email_address as email_contact
FROM ACCOUNTS A
INNER JOIN ACCOUNTS_CONTACTS AS AC ON A.id = AC.account_id
INNER JOIN CONTACTS AS C ON C.id = AC.contact_id
LEFT JOIN EMAIL_ADDR_BEAN_REL AS ER ON ER.bean_id = A.id
AND ER.bean_module = "Accounts"
LEFT JOIN EMAIL_ADDR_BEAN_REL AS ER_C ON ER_C.bean_id = C.id
AND ER_C.bean_module = "Contacts"
LEFT JOIN EMAIL_ADDRESSES AS EA ON ER.email_address_id = EA.id
LEFT JOIN EMAIL_ADDRESSES AS EA_C ON ER_C.email_address_id = EA_C.id
这个查询将返回与同用户相关联的两排,有除了电子邮件地址完全相同的信息,我想有第二个电子邮件地址(或其他电子邮件)添加到同一行,并没有创建额外的行。
帮助将不胜感激!
答
SELECT ... GROUP_CONCAT(email_address) ...
FROM ...
GROUP BY A.id;
这并没有提供问题的答案。要批评或要求作者澄清,请在其帖子下方留言。 – Jatin
@Jatin:是的。问题是“我想将第二个电子邮件地址(或其他电子邮件)添加到同一行,并且没有创建额外的行。”没有为他编写所有代码,这提供了一个缺少的线索 - '' GROUP_CONCAT'加上'GROUP BY'。 –
@RickJames非常感谢你的工作,但是我希望每封电子邮件都在一个单独的专栏中。例如:email_1:[email protected],email_2:[email protected],email_3:[email protected]等。这将所有电子邮件放在一列中用逗号分隔。 – dantheman