Linux和Windows毫秒时间

问题描述：

我想获得系统的毫秒时间（我不在乎它是否是实时，我希望它尽可能准确）。这是一个很好的方法吗？Linux和Windows毫秒时间

#ifdef WIN32 
unsigned long long freq; 
unsigned long long get_ms_time() { 
    LARGE_INTEGER t; 
    QueryPerformanceCounter(&t); 
    return t.QuadPart/freq; 
} 
#else 
unsigned long long get_ms_time() { 
    struct timespec t; 
    clock_gettime(CLOCK_MONOTONIC, &t); 
    return t.tv_sec * 1000 + t.tv_nsec/1000000; 
} 
#endif

如何将此值包裹到signed int？我尝试这样做，并得到像这样的负值（在Linux上，我不知道在Windows上）：

~ start 
-2083002438 
~ 15 seconds after.. 
-2082987440 
~ 15 seconds after.. 
-2082972441

我会这样。〜开始 X 〜15秒后.. X + 14998 〜15秒后.. X + 29997

当X是一个正数。（我想输出正和增加）

你为什么不告诉我们你的代码？ – Nick 2013-05-09 11:30:18

你显示的代码看起来不错，所以我怀疑你打印的是错误的值+或者做了其他错误。 – 2013-05-09 11:37:28

int x =（int）get_ms_time（）; cout dan 2013-05-09 11:37:45

答

我做这样的事情在我的代码...

timespec specStart, specStop; 

// Get start time (UNIX timestamp) in seconds... 
clock_gettime(CLOCK_MONOTONIC_RAW, &startTime); 

int startTimeInt = startTime.tv_sec; 
std::cout << "start time : " << startTimeInt << std::endl; 

... 
// Get stop time (UNIX timestamp) in seconds... 
clock_gettime(CLOCK_MONOTONIC_RAW, &stopTime); 

int stopTimeInt = stopTime.tv_sec; 
std::cout << "stop time : " << stopTimeInt << std::endl; 

// Get time diff from stop time to start time 
unsigned long long timeStart = specStart.tv_sec * 1000000000 + specStart.tv_nsec; 
unsigned long long timeStop = specStop.tv_sec * 1000000000 + specStop.tv_nsec; 
unsigned long long timeDelta = timeStio - timeStart; // Time diff in nanoseconds. 

int microSec = timeDelate/1000; 
int mSec = timeDelta/1000000; 
int sec = timeDelta/1000000000; 

std::cout << "time diff : " << std::endl 
    << sec << " s" << std::endl 
    << msec << " ms" << std::endl 
    << microSec << " µs" << std::endl 
    << timeDelta << " ns" << std::endl;

Linux和Windows毫秒时间

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