Monotouch：获取x.y或点击UIView

Question

我有一个简单的全屏UIView。当用户在屏幕上点击时，我需要写出x，y

Console.WriteLine ("{0},{1}",x,y); 

什么API我需要使用它吗？

Answer 1

在MonoTouch的（因为你在C＃问......虽然以前的答案是正确的:)这将是：

public override void TouchesBegan (NSSet touches, UIEvent evt) 
{ 
    base.TouchesBegan (touches, evt); 

    var touch = touches.AnyObject as UITouch; 

    if (touch != null) { 
     PointF pt = touch.LocationInView (this.View); 
     // ... 
} 

你也可以使用一个UITapGestureRecognizer：

var tapRecognizer = new UITapGestureRecognizer(); 

tapRecognizer.AddTarget(() => { 
    PointF pt = tapRecognizer.LocationInView (this.View); 
    // ... 
}); 

tapRecognizer.NumberOfTapsRequired = 1; 
tapRecognizer.NumberOfTouchesRequired = 1; 

someView.AddGestureRecognizer(tapRecognizer); 

手势识别器很好，因为它们将触摸封装到可重用类中。

Answer 2

-(void) touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event 
{ 
    UITouch *touch = [touches anyObject]; 

    printf("Touch at %f , %f \n" , [touch locationInView:self.view].x, [touch locationInView:self.view].y); 
}