SQL查询:这可以在没有嵌套查询的情况下完成吗?
问题描述:
下面的查询工作,但是非常计算昂贵(有> 14k条记录);这可以更有效地完成(例如,没有嵌套查询)? 基本上它与同一个表中的实例相匹配,它们代表开启命令(log1)和第一个关闭命令(log2)。SQL查询:这可以在没有嵌套查询的情况下完成吗?
SELECT log1.`deviceID`, log1.`timestamp` AS `on`, log2.`timestamp` as `off`
FROM `HC2_log_raw` log1, `HC2_log_raw` log2
WHERE log1.`newValue` > 0 AND log1.`oldValue` = 0 AND log2.`newValue` = 0 AND log1.`deviceID` = log2.`deviceID` AND
log2.`timestamp` =
(SELECT MIN(log3.`timestamp`)
FROM `HC2_log_raw` log3
WHERE log3.`timestamp` > log1.`timestamp` AND log3.`deviceID` = log1.`deviceID` AND log3.`newValue`=0)
谢谢!
答
你可以尝试使用JOIN 与GROUP BY和MIN功能存档您预期的结果
SELECT log1.`deviceid`,
log1.`timestamp` AS `on`,
MIN(log2.`timestamp`) AS `off`
FROM `hc2_log_raw` log1
INNER JOIN `hc2_log_raw` log2
ON log1.`deviceid` = log2.`deviceid`
AND log1.`timestamp` < log2.`timestamp`
WHERE log1.`newvalue` > 0
AND log1.`oldvalue` = 0
AND log2.`newvalue` = 0
GROUP BY log1.`deviceid`, log1.`timestamp`
答
检查了这一点。 afaik,where
子句比加入on
条件更好。
SELECT log1.`deviceID`
,log1.`timestamp` AS `on`
,log2.`timestamp` AS `off`
FROM
`HC2_log_raw` log1
inner join `HC2_log_raw` log2
on
log1.`deviceID` = log2.`deviceID`
where
(
log1.`newValue` > 0
AND log1.`oldValue` = 0
AND log2.`newValue` = 0
AND log2.`timestamp` = (
SELECT MIN(log3.`timestamp`)
FROM `HC2_log_raw` log3
WHERE log3.`timestamp` > log1.`timestamp`
AND log3.`deviceID` = log1.`deviceID`
AND log3.`newValue` = 0
)
)
14K记录并不是很多。 你有没有看过执行计划? 您可能只是需要一个索引 –
您是否在连接条件列上使用索引? –
它不会帮助性能,但是您应该切换到明确的'join'语法,这是自1992年以来的ANSI标准! – HoneyBadger