二元运算符'=='不能应用于'String？'类型的操作数和 '布尔' 的斯威夫特3

Question

var is_searching: String? = nil 

public func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell   
{ 
    let cell = collectionView.dequeueReusableCell(withReuseIdentifier: "Cell", for: indexPath as IndexPath) as! ProductCell 

    if is_searching == true 
    { 
     cell.lblBrndname?.text=(searched_array[(indexPath as NSIndexPath).row] as AnyObject).value(forKey: "brand_name") as? String 
     cell.Pdtimg?.image = UIImage(named: icon_Array[indexPath.row]) 

    } 
    else 
    { 
     cell.lblBrndname?.text=(Specarray[(indexPath as NSIndexPath).row] as AnyObject).value(forKey: "brand_name") as? String 
     cell.Pdtimg?.image = UIImage(named: self.icon_Array[indexPath.row]) 

    } 
    return cell 

} 

Answer 1

变型isSearching

的

var is_searching: Bool = false 

Answer 2

的NSString有，你可以用一个boolValue属性：

if let is_searching = is_searching as? NSString, 
    is_searching.boolValue == true { 
    print("String is true") 
} else { 
    print("String is not true") 

但其他海报的想法是更好的。如果你可以重写你的代码，那么is_searching首先是一个更好的方法。