瓷砖尺寸算法
我在C++中制作瓷砖游戏。现在,当游戏加载所有的瓷砖把自己基于:瓷砖尺寸算法
tilesize - >它们是正方形所以这是宽度和高度
tile_count_x
tile_count_y
我有以下变量:
desktop_width
desktop_height
game_window_width
game_window_height
tile_count_x
tile_count_y
基于这些价值观,我正在寻找一种算法,将设置给出的台式机和tile_count限制适当的窗口大小。然后在此,我希望我的瓷砖有偏移,将边境X%左右,这将根本决定tilesize太窗口:
例子: 如果我有瓷砖那么10 * 3:
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Window Title _[]X
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| [][][][][][][][][][] |
| [][][][][][][][][][] |
| [][][][][][][][][][] |
| |
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我只是不确定需要这样做的公式。
编辑(从评论):
- Tilesize变化,tilecountx和y是静态
- 我想,因为它可以给桌面分辨率的gamewindow应象大,但我也希望它的方面比尊重tilecoutx和tilecounty
,我发现我的意思的例子,在Windows
这是我如何解决它......
//WINDOW SIZE SETUP
//choose the smaller TILE_SIZE
if (DESKTOP_WIDTH/TILE_COUNT_X > DESKTOP_HEIGHT/TILE_COUNT_Y)
{
TILE_SIZE = DESKTOP_HEIGHT/TILE_COUNT_Y;
}
else
{
TILE_SIZE = DESKTOP_WIDTH/TILE_COUNT_X;
}
//Set screen size and consider a 5 tile border
SCREEN_WIDTH = TILE_SIZE * (TILE_COUNT_X + 5);
SCREEN_HEIGHT = TILE_SIZE * (TILE_COUNT_Y + 5);
//resize window until it satisfies resolution constraints
while(SCREEN_WIDTH > (DESKTOP_WIDTH - (DESKTOP_WIDTH * 0.07)))
{
TILE_SIZE --;
SCREEN_WIDTH = TILE_SIZE * (TILE_COUNT_X + 5);
SCREEN_HEIGHT = TILE_SIZE * (TILE_COUNT_Y + 5);
}
while(SCREEN_HEIGHT > (DESKTOP_HEIGHT - (DESKTOP_HEIGHT * 0.15)))
{
TILE_SIZE -- ;
SCREEN_WIDTH = TILE_SIZE * (TILE_COUNT_X + 5);
SCREEN_HEIGHT = TILE_SIZE * (TILE_COUNT_Y + 5);
}
for(int i = 0; i < 8; ++i) //Ensure resolution is multiple of 8
{
if (SCREEN_WIDTH % 8 != 0) //remainder means not multiple of 8
{
SCREEN_WIDTH += 1;
}
if (SCREEN_HEIGHT % 8 != 0)
{
SCREEN_HEIGHT += 1;
}
}
X_OFFSET = (SCREEN_WIDTH - (TILE_SIZE * TILE_COUNT_X))/2;
Y_OFFSET = (SCREEN_HEIGHT - (TILE_SIZE * TILE_COUNT_Y))/2;
简单的线性代数开辟扫雷:
game_window_width = (tile_count_x * TILE_WIDTH) + 2*(game_window_width * X/100)
我们有2个变量(TILE_WIDTH
和X
),只有1方程,所以,嗯,你的运气了。
您需要指定TILE_WIDTH
或X
(余量)。比方说,你指定X
,那么你就可以解这个方程:
TILE_WIDTH = (game_window_width - (2*(game_window_width * X/100)))/
tile_count_x
如果我们考虑到的高度,并要求相同的边框,然后我们有2个方程和3个未知数。还是SOL。
我不是一个C++程序员,但你应该得到的东西这样的:
// Amount of padding to leave around tiles (of window size)
int percentage = 10;
tile_ratio = tile_count_x/tile_count_y;
desktop_ratio = desktop_width/desktop_height;
// Determine the maximum window width and height
// according to tile and desktop aspect ratios
if(tile_ratio >= desktop_ratio) {
window_width = desktop_width;
window_height = window_width * (1/tile_ratio);
} else {
window_height = desktop_height;
window_width = window_height * tile_ratio;
}
// Determine maximum width and height for tiles,
// taking account x% of padding on both sides, hence the * 2
tile_width = window_width * ((100 - (percentage * 2))/100);
tile_height = window_height * ((100 - (percentage * 2))/100);
// As the tiles must be square, determine the smaller side as the size
tile_size = tile_width < tile_height ? tile_width : tile_height;
// To maintain the x% padding, we must calculate the window size again as we just changed the tilesize
factor = (100/(100 - (percentage * 2)));
window_width = tile_size * tile_count_x * factor;
window_height = tile_size * tile_count_y * factor;
现在你有最大窗口的宽度和高度,使:
- 窗口是在与瓷砖相同的宽高比
- 窗口不大于桌面
- 该窗口在瓷砖的所有边上都有x%的填充度
请注意,我还没有测试过这个代码,但它应该工作。如果您发现任何错误,请尝试了解我尝试执行的操作并相应地进行修复。
如果您使用的是Win32,那么您可以使用类似下面的内容来初始调整窗口的客户区大小。
initial_width = (tile_count_x * tile_size) + (border_width * 2);
initial_height = (tile_count_y * tile_size) + (border_width * 2);
当窗口临危调整事件则只需stretchblt每一瓦片(即放大或缩小每个瓦片)通过该窗口已经膨胀或由(假设轴被锁定收缩的像素的数量,即你无法调整每个独立的)。
换句话说,TILE_SIZE会有所不同:
tile_size += window_resize_amount;
此代码是从存储器,但它可能给予一个想法。
DWORD dwStyle = WS_POPUP | WS_BORDER | WS_SYSMENU | WS_MINIMIZEBOX | WS_CAPTION;
DWORD dwExStyle = 0;
int border_width = tile_size; // make border 1 tile
RECT r, w;
SetRect(&r, 0, 0, (tile_count_x * tile_size) + (border_width * 2), (tile_count_y * tile_size) + (border_width * 2));
AdjustWindowRectEx(&r, dwStyle, FALSE, dwExStyle);
SystemParametersInfo(SPI_GETWORKAREA, 0, &w, 0);
int width = r.right - r.left;
int height = r.bottom - r.top;
int x = ((w.right - w.left)/2) - (width/2);
int y = ((w.bottom - w.top)/2) - (height/2);
hWnd = CreateWindowEx(dwExStyle, szClassName, szAppName, dwStyle, x, y, width, height, NULL, NULL, hInstance, 0);
根据窗口/桌面大小是否平铺尺寸变化或者你想改变瓦数,以适应窗口还是什么?你可以编辑你的帖子而不是评论它。 – 2009-12-13 17:01:40
我认为那是对我提出的评论的回复。我删除了评论,因为我认为我读了问题中的答案。 – keyboardP 2009-12-13 17:03:17
Tilesize变化,tilecountx和y是静态的 – jmasterx 2009-12-13 17:03:17