如何在iphone应用程序中的UITableCell中加载图像

Question

我开发了一个RSS应用程序。在我的表格单元格中，我显示的图像是从RSS feed和Title中的图像链接中检索的。 图像已成功加载，但问题是它挂起我的应用程序。 有没有办法在后台加载图片。 我现在的代码是。

int blogEntryIndex1 = [indexPath indexAtPosition: [indexPath length] -1]; 
     imgstring=[[blogEntries objectAtIndex: blogEntryIndex1] objectForKey: @"image"]; 
NSURL *url = [NSURL URLWithString:imgstring]; 
    NSData *data = [NSData dataWithContentsOfURL:url]; 
    UIImage *img = [[UIImage alloc] initWithData:data]; 
    cell.imageView.image=[img autorelease]; 

任何想法请，在此先感谢...

Answer 1

转播......你也应该看看懒加载表通过苹果的示例代码http://developer.apple.com/iphone/library/samplecode/LazyTableImages/Introduction/Intro.html

更新另一个例子在这里：http://www.markj.net/iphone-asynchronous-table-image/

Answer 2

并且从Apple看看这个文件。

http://developer.apple.com/iphone/library/documentation/cocoa/Conceptual/URLLoadingSystem/URLLoadingSystem.html

大多数我用NSURLConnection下载东西的时候。

Answer 3

那么家伙，我已经做了它的代码是...

- (void) loadImage:(id)object { 
NSAutoreleasePool *pool = [[NSAutoreleasePool alloc] init]; 

// Get the data to pass in 
NSDictionary *dict = (NSDictionary *)object; 

// Get the cell and the image string 
NSString *imgstring = [dict objectForKey:@"imgstring"]; 
MyfirstCell *cell = [dict objectForKey:@"cell"]; 

NSURL *url = [NSURL URLWithString:imgstring]; 
NSData *data = [NSData dataWithContentsOfURL:url]; 
UIImage *img = [[UIImage alloc] initWithData:data]; 
    cell.myimnage.image = img; 
[pool release]; 

}

我会打电话给上面的方法在我的代码...

if(searching) { 
     //cell.textLabel.text = [copyListOfItems objectAtIndex:indexPath.row]; 
     int blogEntryIndex = [indexPath indexAtPosition: [indexPath length] -1]; 
     // Tell your code to load the image for a cell in the background 
     NSString *imgstring =[[blogEntries objectAtIndex: blogEntryIndex] objectForKey: @"image"]; 
     NSDictionary *dict = [NSDictionary dictionaryWithObjectsAndKeys:cell, @"cell", imgstring, @"imgstring", nil]; 
     [self performSelectorInBackground:@selector(loadImage:) withObject:dict]; 
     //background code end here.. 

感谢deanWombourne谁给了我这个代码....

Answer 4

你可以这样使用：

((UIImageView *)cell.backgroundView).image = bgImage; 
((UIImageView *)cell.selectedBackgroundView).image = bgImage;