比较两个对象，并返回唯一的数据

Question

我有两个对象，我只想提取使用下划线js唯一的数据。

对象1（默认）

{ 
    players: "Players: ", 
    tableLimit: "Table Limits:", 
    newCardBtn: "Add New Card", 
    existingCard: "Use existing one", 
    contactUs: "Contact Us", 
    test: { 
     table: 'test' 
    } 
} 

对象2（改写）

{ 
    players: "Players: ", 
    tableLimit: "Table Limits:", 
    newCardBtn: "Add New Card", 
    existingCard: "Use existing one", 
    test: { 
     table: 'test' 
    } 
    } 

最终结果应当返回一个列表与从重写缺失数据。在我们的例子中，它应该返回contactUs: "Contact Us"

到现在我有这个，但它返回的默认对象中的所有数据，而无需自定义：

var def = { 
    players: "Players: ", 
    tableLimit: "Table Limits:", 
    newCardBtn: "Add New Card", 
    existingCard: "Use existing one", 
    contactUs: "Contact Us", 
    test: { 
     table: 'test' 
    } 
} 

var custom = { 
    players: "Players: ", 
    tableLimit: "Table Limits:", 
    newCardBtn: "Add New Card", 
    existingCard: "Use existing one", 
    test: { 
     table: 'test' 
    } 
} 

var out = JSON.stringify(Object.assign({}, def, custom)); 
fs.writeFile("./out.js", out); 

Answer 1

这将解析OBJ1，如果没有匹配的属性与匹配值obj2然后它被添加到obj3。你可以看到在输出的结果...

var obj1 = { 
 
    players: "Players: ", 
 
    tableLimit: "Table Limits:", 
 
    newCardBtn: "Add New Card", 
 
    existingCard: "Use existing one", 
 
    contactUs: "Contact Us", 
 
}; 
 

 
var obj2 = { 
 
    players: "Players: ", 
 
    tableLimit: "Table Limits:", 
 
    newCardBtn: "Add New Card", 
 
    existingCard: "Use existing one", 
 
}; 
 
    
 
var obj3 = (function() { 
 
    result = {}; 
 
    for (var k in obj1) { 
 
    if (obj2[k] != obj1[k]) { 
 
     result[k] = obj1[k]; 
 
    } 
 
    } 
 
    return result; 
 
})(); 
 

 
console.log(obj3);