从我的iOS 5应用程序打开Twitter应用程序
问题描述:
我想从iOS 5中的应用程序中打开Twitter应用程序,但它不会打开。任何帮助将不胜感激,我已经包括我在下面使用的代码。从我的iOS 5应用程序打开Twitter应用程序
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"prefs:root=TWITTER"]];
请帮助我,并提前致谢!
答
你想推出Twitter应用程序,还是只发送你的应用程序内的推文?我相信您上面显示的代码是在您的设置应用中启动Twitters偏好设置......我也相信已被禁止使用5.1
如果您希望将Twitter集成添加到您的应用中Apple提供了很好的示例代码向你展示如何在iOS 5中使用推特内置的Twitter框架使用Twitter。
现在我建议你下载这个示例代码,看看还有什么需要发送推文(如检查CanTweetStatus),但我附加如何在这篇文章中发送推文的基本思路。
- (IBAction)sendCustomTweet:(id)sender {
// Create an account store object.
ACAccountStore *accountStore = [[ACAccountStore alloc] init];
// Create an account type that ensures Twitter accounts are retrieved.
ACAccountType *accountType = [accountStore accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];
// Request access from the user to use their Twitter accounts.
[accountStore requestAccessToAccountsWithType:accountType withCompletionHandler:^(BOOL granted, NSError *error) {
if(granted) {
// Get the list of Twitter accounts.
NSArray *accountsArray = [accountStore accountsWithAccountType:accountType];
// For the sake of brevity, we'll assume there is only one Twitter account present.
// You would ideally ask the user which account they want to tweet from, if there is more than one Twitter account present.
if ([accountsArray count] > 0) {
// Grab the initial Twitter account to tweet from.
ACAccount *twitterAccount = [accountsArray objectAtIndex:0];
// Create a request, which in this example, posts a tweet to the user's timeline.
// This example uses version 1 of the Twitter API.
// This may need to be changed to whichever version is currently appropriate.
TWRequest *postRequest = [[TWRequest alloc] initWithURL:[NSURL URLWithString:@"http://api.twitter.com/1/statuses/update.json"] parameters:[NSDictionary dictionaryWithObject:@"Hello. This is a tweet." forKey:@"status"] requestMethod:TWRequestMethodPOST];
// Set the account used to post the tweet.
[postRequest setAccount:twitterAccount];
// Perform the request created above and create a handler block to handle the response.
[postRequest performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {
NSString *output = [NSString stringWithFormat:@"HTTP response status: %i", [urlResponse statusCode]];
[self performSelectorOnMainThread:@selector(displayText:) withObject:output waitUntilDone:NO];
}];
}
}
}];
}
祝您好运!
答
如果你只是试图打开实际的Twitter的应用程序,然后将代码
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"twitter://"]];
它打开Twitter的应用程序不是Twitter的设置。 – PJR 2012-07-04 08:20:32
不允许从应用程序打开偏好设置 – Otium 2012-07-04 21:02:25