从表中列的最大值和最小值

问题描述:

enter image description here我有一个表格中有以下数据,我试图从表格中获取最大值和最小值列。如果它是一列,我可以使用列的最大/最小值,但在这里我是比较表中的所有列。我需要的是添加新列以存储最大和最小数据。从表中列的最大值和最小值

而且将只有一个行的表提前

create table 
#test (column1 int, column2 int , column3 int , column4 int ,column5 int,column6 int) 

insert into #test 
values(89, 103,87,67,86,56) 

select * from #test 

--drop table #test 

感谢。

+0

您可以取消转换序列(https://technet.microsoft.com/en-us/library/ms177410(v=sql.105).aspx),然后取最大值/最小值 – Jeremy

最简单的方法就是交叉应用列的最小值/最大值。例如对于:

SELECT * 
FROM #test t 
CROSS APPLY (
    SELECT MAX(val), MIN(val) 
    FROM (VALUES (t.column1), (t.column2), (t.column3), (t.column4), (t.column5), (t.column6)) AS c(val) 
) AS c(maxvalue, minvalue); 

使用VALUES方法unpivot的数据,然后reaggravating它将使一个更清晰的语法,但它确实会带来成本的性能(不可怕,但它的存在)。使用CASE表达式是有点更麻烦,但在语法部门,尤其是如果有很多列来进行评估,但你不会发生同样的性能损失...

SELECT 
    t.column1, t.column2, t.column3, t.column4, t.column5, t.column6, 
    MinValue = CASE 
        WHEN t.column1 <= t.column2 AND t.column1 <= t.column3 AND t.column1 <= t.column4 AND t.column1 <= t.column5 AND t.column1 <= t.column6 THEN t.column1 
        WHEN t.column2 <= t.column1 AND t.column2 <= t.column3 AND t.column2 <= t.column4 AND t.column2 <= t.column5 AND t.column2 <= t.column6 THEN t.column2 
        WHEN t.column3 <= t.column1 AND t.column3 <= t.column2 AND t.column3 <= t.column4 AND t.column3 <= t.column5 AND t.column3 <= t.column6 THEN t.column3 
        WHEN t.column4 <= t.column1 AND t.column4 <= t.column2 AND t.column4 <= t.column3 AND t.column4 <= t.column5 AND t.column4 <= t.column6 THEN t.column4 
        WHEN t.column5 <= t.column1 AND t.column5 <= t.column2 AND t.column5 <= t.column3 AND t.column5 <= t.column4 AND t.column5 <= t.column6 THEN t.column5 
        ELSE t.column6 
       END, 
    MaxValue = CASE 
        WHEN t.column1 >= t.column2 AND t.column1 >= t.column3 AND t.column1 >= t.column4 AND t.column1 >= t.column5 AND t.column1 >= t.column6 THEN t.column1 
        WHEN t.column2 >= t.column1 AND t.column2 >= t.column3 AND t.column2 >= t.column4 AND t.column2 >= t.column5 AND t.column2 >= t.column6 THEN t.column2 
        WHEN t.column3 >= t.column1 AND t.column3 >= t.column2 AND t.column3 >= t.column4 AND t.column3 >= t.column5 AND t.column3 >= t.column6 THEN t.column3 
        WHEN t.column4 >= t.column1 AND t.column4 >= t.column2 AND t.column4 >= t.column3 AND t.column4 >= t.column5 AND t.column4 >= t.column6 THEN t.column4 
        WHEN t.column5 >= t.column1 AND t.column5 >= t.column2 AND t.column5 >= t.column3 AND t.column5 >= t.column4 AND t.column5 >= t.column6 THEN t.column5 
        ELSE t.column6 
       END 
FROM 
    #test t; 

结果...

column1  column2  column3  column4  column5  column6  MinValue MaxValue 
----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- 
89   103   87   67   86   56   56   103 

我发现这个解决方案here

SELECT 
    column1 
    ,column2 
    ,column3 
    ,column4 
    ,column5 
    ,column6 
    ,(SELECT MAX(MaxValue) 
     FROM (VALUES (column1),(column2),(column3), (column4), (column5), (column6)) AS [Values](MaxValue)) 
    AS MaxValue 
    ,(SELECT MIN(MinValue) 
     FROM (VALUES (column1),(column2),(column3), (column4), (column5), (column6)) AS [Values](MinValue)) 
    AS MinValue 
FROM #test