如何制作程序来计算每个单词的值

问题描述：

我试图让程序计算每个单词的值，如果a是1，b是2，c是3，依此类推。我已经完成了大部分代码，但它不起作用。任何人都可以给我一些建议吗？我最近才开始学习python，那么你能尽可能详细吗？谢谢。如何制作程序来计算每个单词的值

__author__ = "Anthony Chen" 
__copyright__ = "Copyright (C) 2017 Anthony Chen" 
__license__ = "Public Domain" 
__version__ = "1.0" 

output = ('None') 
worth = {'a':1, 
'b':2, 
'c':3, 
'd':4, 
'e':5, 
'f':6, 
'g':7, 
'h':8, 
'i':9, 
'j':10, 
'k':11, 
'l':12, 
'm':13, 
'n':14, 
'o':16, 
'q':17, 
'r':18, 
's':19, 
't':20, 
'u':21, 
'v':22, 
'w':23, 
'x':24, 
'y':25, 
'z':26, 
} 


def findworth(): 
    for char in wordlist: 
     if char in wordlist: 
      output = (worth[char]) 
      wordlist.replace(output) 
     elif worth[char] == False: 
      output = (None) 

while True: 
    output = (None) 
    wordlist = [] 
    word = input(str("Find out how many cents your word is worth. Please enter your word:")) 
    word = word.lower() 
    wordlist = list(word) 
    wordlist = findworth() 
    output = sum(wordlist) 
    print("Your word's value is:") 
    print (output) 
    print('.')

这是什么节目，当我运行它：

**Find out how many cents your word is worth. Please enter your word:Bananas 
Traceback (most recent call last): 
    File "C:/Anthony/School/__CentsWord/WordWorth.py", line 49, in <module> 
    wordlist = findworth() 
    File "C:/Anthony/School/__CentsWord/WordWorth.py", line 39, in findworth 
    wordlist.replace(output) 
AttributeError: 'list' object has no attribute 'replace'**

我知道。我只是不知道如何解决它。 –

python'list'没有'replace'函数，在遍历它时修改列表也是一种冒险的做法。这可能会导致各种问题。此外，你的主循环期望你的'findworth'函数返回一个数字列表，目前它不会。所以你可以在'findworth'函数开头定义一个空列表，然后在迭代列表中追加每个字符的值。 – Eric

只是为了好玩，试试'print（sum（ord（c） - 96 for c in“hello”））''。仅适用于小写a-z。 –

答

根据您的解决方案（它不是海事组织非常好，将提供一个更好的）

def findworth(): 
    for i,char in enumerate(wordlist): 
     if char in worth: 
      output = (worth[char]) 
      wordlist[i] = (output) 
     else: 
      output = (None) 

while True: 
    output = (None) 
    wordlist = [] 
    word = input(str("Find out how many cents your word is worth. Please enter your word:")) 
    word = word.lower() 
    wordlist = list(word) 
    findworth() 
    output = sum(wordlist) 
    print("Your word's value is:") 
    print (output) 
    print('.')

一通过减少冗余更好的解决方案

while True: 
    word = input(str("Find out how many cents your word is worth. Please enter your word:")) 
    word = word.lower() 
    output = 0 # set initial value 
    for char in word: # iterate string for each character 
     if char in worth: # check if its a valid char 
      output += worth[char] # same as output = output + worth[char] 

    print("Your word's value is:") 
    print (output) 
    print('.')

Python的字符串已经是迭代的，所以你不必把它做成一个列表:)

'output = sum（word.lower（）如果char值在char中，值为[char]'，'sum（）'理解将'for'循环减少为一行，节省足够的空间来添加停止条件：'如果不输出：中断' – f5r5e5d

答

对于避免了更先进的技术解决方案：

worth = { 
    'a':1, 'b':2, 'c':3, 'd':4, 'e':5, 'f':6, 'g':7, 
    'h':8, 'i':9, 'j':10, 'k':11, 'l':12, 'm':13, 'n':14, 
    'o':15, 'q':17, 'r':18, 's':19, 't':20, 'u':21, 
    'v':22, 'w':23, 'x':24, 'y':25, 'z':26} 

def findworth(word): 
    total = 0 
    for char in word: 
     if char in worth: 
      total += worth[char] 
    return total 

print("Find out how many cents your word is worth.") 

while True: 
    word = input("Please enter your word: ").lower() 
    print("Your word's value is:", findworth(word))

给你输出如下：

Find out how many cents your word is worth. 
Please enter your word: abc 
Your word's value is: 6 
Please enter your word: hello 
Your word's value is: 53

注：worth目前缺少p，使o不正确的值，这也许应该是：

worth = { 
    'a':1, 'b':2, 'c':3, 'd':4, 'e':5, 'f':6, 'g':7, 
    'h':8, 'i':9, 'j':10, 'k':11, 'l':12, 'm':13, 'n':14, 
    'o':15, 'p':16, 'q':17, 'r':18, 's':19, 't':20, 'u':21, 
    'v':22, 'w':23, 'x':24, 'y':25, 'z':26}

是你好不是52的分数？ –

通常情况是，但是OP给出'o'为'16'而不是'15'。 –

他们发现了，他们忘了'p' –

答

我的第一个评论是用来产生worth的方法是很长篇大论，因此容易出错，事实上，看来你已经忘了'p'，而是使用'o':16。您可以代替生成你使用字典理解实在值得的名单：

worth = {chr(x+96):x for x in range(1,27)}

这是通过遍历数字1..26，并转换n + 96一个字符（使用ASCII表中看到，97 'a'， 98 'b'等等，这个人物，然后作为关键值

接下来，我们可以生成单词中的每个字符值的列表：

word = "hello" 
scores = [worth[c] for c in word]

这将会给我们scores == [8, 5, 12, 12, 5]。

最后，你可以调用sum函数中添加了所有的值的列表：

sum(scores)

返回52。

你可以把这个连成一个函数来获取：

def get_word_score(word): 
    worth = {chr(x+96):x for x in range(1,27)} 
    scores = [worth[c] for c in word] 
    return sum(scores)

或者这可以在1号线进行搭配：

sum([ord(c)-96 for c in word])

ord做的chr相反，它返回的ASCII给出的字符的值。

作为使用词'hello'的sum([ord(c)-96 for c in word])的演练。第一步是让每个字符转换为列表：减去96

>>> [ord(c) for c in 'hello'] 
[104, 101, 108, 108, 111]

下一页每个ASCII值转换为字母的位置是：：

>>> [c for c in 'hello'] 
['h', 'e', 'l', 'l', 'o']

接下来的每个字符转换为字符的ASCII值

>>> [ord(c)-96 for c in 'hello'] 
[8, 5, 12, 12, 15]

最后总和：

>>> sum([ord(c)-96 for c in 'hello']) 
52

然后

你的代码的功能是：

while True: 
    word = input("Find out how many cents your word is worth. Please enter your word:").lower() 
    output = sum([ord(c)-96 for c in word]) 
    print("Your word's value is:", output, ".")

如何制作程序来计算每个单词的值

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