如何确保在检查时仅将值保存到表中?
用我的代码在这里,如果用户选中名称 其中一个名称旁边的复选框,则当用户单击“保存”时,名称将保存到我的review_shared表中。如何确保在检查时仅将值保存到表中?
但我想要一个选中的值只保存 一次到表中,现在它被保存多次 - 我的意思是,如果用户回到这个页面,名称被选中,用户点击再次保存。
我可以添加到代码中要做到这一点什么,所以它只会在我review_shared表保存一次?目前,它看起来是这样的,它多次将其保存:
if(!empty($_POST['check_contacts'])) {
foreach($_POST['check_contacts'] as $check) {
//$_GET['id'] is the current review for which contacts are being edited, we are checking a contact to share that review with
$insert_review_shared_command = "INSERT INTO review_shared VALUES(NULL," .$_GET['id']. ", '$user_id','$check')";
//we want to save the checked contacts into the review_shared table
$insert_into_review_shared_table = mysqli_query($con,$insert_review_shared_command);
}
//go to the main page when changes have been saved
header('Location:volleyLogin.php');
}
$con->close();
我想加入这样的代码到上面会有所帮助,但事实并非如此,真正做到:
if(!empty($_POST['check_contacts'])) {
//************************* added this in **************
$check="";
//if the contact in review_shared is already checked, we don't want to save it multiple times
$already_checked = "SELECT * from review_shared WHERE user_id = '$user_id' AND contact_id = '$check' AND review_id = " .$_GET['id'];
$already_checked_result=mysqli_query($con,$already_checked);
$num_rows = mysqli_num_rows($already_checked_result);
if($num_rows >= 1) {
echo "This is already a contact";
break;
}
//*******************************************************
foreach($_POST['check_contacts'] as $check) {
//$_GET['id'] is the current review for which contacts are being edited, we are checking a contact to share that review with
$insert_review_shared_command = "INSERT INTO review_shared VALUES(NULL," .$_GET['id']. ", '$user_id','$check')";
//we want to save the checked contacts into the review_shared table
$insert_into_review_shared_table = mysqli_query($con,$insert_review_shared_command);
}
//go to the main page when changes have been saved
header('Location:volleyLogin.php');
}
$con->close();
break;
使用来自循环(for
,foreach
,while
和do-while
)和switch
结构,而不是从if
块。你必须创建一个对应于的else
块,即if
块,并将整个foreach
循环放在那里。
// your code
if($num_rows) {
echo "This is already a contact";
}else{
foreach($_POST['check_contacts'] as $check) {
//$_GET['id'] is the current review for which contacts are being edited, we are checking a contact to share that review with
$insert_review_shared_command = "INSERT INTO review_shared VALUES(NULL," .$_GET['id']. ", '$user_id','$check')";
//we want to save the checked contacts into the review_shared table
$insert_into_review_shared_table = mysqli_query($con,$insert_review_shared_command);
}
}
// your code
以下是相关的参考:
好的,有用的代码。有了它,我解决了我的问题,将很快发布。它实际上是一个IF和ELSE IF块,我使用。 – CHarris
@ChristopheHarris很高兴的答案帮助你解决了这个问题。 :-) –
这是更好地使字段名称独特的字段,这样就可以让数据库面对这一切。使用'insert ... on duplicate key update'。不需要这样的初始查询。 – apokryfos