小吃吧只适用于某一类
问题描述:
我试图与add-culture-button
类的所有按钮添加事件侦听器小吃吧的一个元素,但它仅适用于第一个元素。对于其他元素,小吃吧不显示在所有(也有在控制台没有错误)。小吃吧只适用于某一类
var snackbarContainer = document.querySelector("#notification");
var showSnackbarButton = document.querySelector(".add-culture-button");
var plantingLabel = document.querySelector("#planting-label");
var handler = function(event) {
var culturesCount = parseInt(plantingLabel.attributes["data-badge"].value);
plantingLabel.setAttribute("data-badge", culturesCount - 1);
}
showSnackbarButton.addEventListener("click", function() {
var culturesCount = parseInt(plantingLabel.attributes["data-badge"].value);
plantingLabel.setAttribute("data-badge", culturesCount + 1);
var data = {
message: "Kultura je dodata u listu za setvu.",
timeout: 2000,
actionHandler: handler,
actionText: 'Opozovi'
};
snackbarContainer.MaterialSnackbar.showSnackbar(data);
});
有没有办法让所有的元素都可以在不重复的情况下工作?
答
原来我只需要使用querySelectorAll
,而不是querySelector
...
var snackbarContainer = document.querySelector("#notification");
var showSnackbarButton = document.querySelectorAll(".add-culture-button");
var plantingLabel = document.querySelector("#planting-label");
var handler = function(event) {
var culturesCount = parseInt(plantingLabel.attributes["data-badge"].value);
plantingLabel.setAttribute("data-badge", culturesCount - 1);
}
for (var i = 0; i < showSnackbarButton.length; i++) {
showSnackbarButton[i].addEventListener("click", function() {
var culturesCount = parseInt(plantingLabel.attributes["data-badge"].value);
plantingLabel.setAttribute("data-badge", culturesCount + 1);
var data = {
message: "Kultura je dodata u listu za setvu.",
timeout: 2000,
actionHandler: handler,
actionText: 'Opozovi'
};
snackbarContainer.MaterialSnackbar.showSnackbar(data);
});
}