在'android'包中找不到属性'onClick'的资源标识符
问题描述:
我在尝试运行我的代码时遇到以下错误。在'android'包中找不到属性'onClick'的资源标识符
我把它搜索出来了。许多人已经谈到了不适用于API < = 3的onclick方法。我重新检查了我的API级别。它是17.
如何获得有关运行我的代码的信息。
如果需要我可以发布我的MainActivity.java代码弄清楚。
这里是代码
package com.example.myfirstapp;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import org.apache.http.HttpResponse;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import android.app.Activity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.AdapterView;
import android.widget.ArrayAdapter;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Spinner;
import android.widget.TextView;
public class MainActivity extends Activity {
private Button btn;
private EditText edit;
private Spinner spinner;
private TextView textView;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
btn = (Button) findViewById(R.id.button);
edit = (EditText) findViewById(R.id.edit_message);
spinner = (Spinner) findViewById(R.id.spinner);
textView = (TextView) findViewById(R.id.textView1);
btn.setOnClickListener(
new View.OnClickListener()
{
public void onClick(View view)
{
//Log.v("EditText", edit.getText().toString());
//Log.v("Spinner", spinner.getSelectedItem().toString());
String url="http://js-server.xxx.edu:23405/examples/servlet/HelloWorldExample?title="+edit.getText().toString()+"&type="+spinner.getSelectedItem().toString();
Log.v("url",url);
}
});
ArrayAdapter<CharSequence> adapter = ArrayAdapter.createFromResource(this,R.array.title_type,android.R.layout.simple_spinner_item);
adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
spinner.setAdapter(adapter);
//String url="http://js-server.xxx.edu:23405/examples/servlet/HelloWorldExample?title="+edit.getText().toString()+"&type="+spinner.getSelectedItem().toString();
// Log.v("url",url);
spinner.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
public void onItemSelected(AdapterView<?> parent, View view, int pos, long id) {
//Object item = parent.getItemAtPosition(pos);
}
public void onNothingSelected(AdapterView<?> parent) {
}
});
}
private class DownloadWebPageTask extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... urls) {
String response = "";
for (String url : urls) {
DefaultHttpClient client = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
try {
HttpResponse execute = client.execute(httpGet);
InputStream content = execute.getEntity().getContent();
BufferedReader buffer = new BufferedReader(new InputStreamReader(content));
String s = "";
while ((s = buffer.readLine()) != null) {
response += s;
}
} catch (Exception e) {
e.printStackTrace();
}
}
return response;
}
@Override
protected void onPostExecute(String result) {
textView.setText(result);
}
}
public void readWebpage(View view) {
DownloadWebPageTask task = new DownloadWebPageTask();
task.execute(new String[] { "http://js-server.xxx.edu:23405/examples/servlet/HelloWorldExample?title="+edit.getText().toString()+"&type="+spinner.getSelectedItem().toString() });
}
}
所有我试图做的是获取由服务器返回的JSON数据。然后我需要解析JSON数据以形成表格格式。我还没有到这个部分,仍然坚持从我的服务器检索JSON数据。
我的XML文件是:
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
<EditText
android:id="@+id/edit_message"
android:layout_width="298dp"
android:layout_height="wrap_content"
android:layout_marginTop="37dp"
android:ems="10"
android:hint="@string/edit_message" />
<Spinner
android:id="@+id/spinner"
android:layout_width="304dp"
android:layout_height="45dp" />
<Button
android:id="@+id/button"
style="?android:attr/buttonStyleSmall"
android:layout_width="106dp"
android:layout_height="wrap_content"
android:onclick="readWebpage"
android:text="@string/button_send" />
<TextView
android:id="@+id/textView1"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:text="Example Text" />
</LinearLayout>
答
Android的XML解析器是大小写敏感的。这是不正确的:
android:onclick="readWebpage"
这是正确的:
android:onClick="readWebpage"
+0
是的。有效 。 – PSN
答
不正确: -
安卓上ç舔= “ReadFun”; (的onclick < = “C” 不首都)
正确: -
机器人:上Ç舔= “ReadFun”; (onclick < =“C”是首都)
请张贴您的代码。另外,在XML中使用onClick通常是一个糟糕的主意。注册一个OnClickListener,而不是。, – Codeman
@ Pheonixblade9:**“...在XML中使用onClick通常是一个糟糕的主意。”** - 您的逻辑背后的逻辑是什么? – Squonk
@Squonk它不易维护。它类似于在JavaScript中使用onClick,它没有明确不正确,这只是不好的做法。 – Codeman