如何从PHP中的MYSQL数据库的下拉列表中插入选中的复选框数据
问题描述:
我有一个注册表单,用户可以通过复选框选择多个选项。但是现在当我尝试将选定的数据插入到数据库中时,它不起作用。下面是一些代码:如何从PHP中的MYSQL数据库的下拉列表中插入选中的复选框数据
HTML代码:
<div class="col-md-6">
<div class="form-group">
<label for="decisions3">Skills</label>
<select name="langOpt2[]" id="langOpt2" multiple="multiple" class="form-control" required data-validation-required-messge="This field is required">
<?php $selectskill = 'select * from skills where status=1';
$dataskill = mysql_query($selectskill);
while($resultskill = mysql_fetch_object($dataskill))
{?>
<option value="<?=$resultskill->skill_name?>"<?php if($result001->skill_name==$resultskill->skill_name){?> selected="selected"<?php } ?> >
<?=$resultskill->skill_name?>
</option>
<?php }
?>
</select>
</div>
的JS
<script>
$('#langOpt').multiselect({
columns: 1,
placeholder: 'Select Languages'
});
$('#langOpt2').multiselect({
columns: 1,
placeholder: 'Select Languages',
search: true
});
$('#langOpt3').multiselect({
columns: 1,
placeholder: 'Select Languages',
search: true,
selectAll: true
});
$('#langOptgroup').multiselect({
columns: 4,
placeholder: 'Select Languages',
search: true,
selectAll: true
});
</script>
,而PHP的: 此代码将数据插入到数据库中。我使用旧的PHP版本插入数据。只是为了练习。
<?php
if(isset($_POST['submit'])){
include("test/admin/includes/db.php");
$skills=$_POST['langOpt2'];
foreach($_POST['langOpt2'] as $skills){
mysql_query("insert into `job_seeker_reg` (`j_skills`) values('','$skills')");
}}
?>
答
贝娄代码帮助解决您的问题。我举个例子是选择科目。你可以使用选项菜单来完成你的任务。
HTML代码:
select subject: <select name="Subject" id="dob-day">
<option ">-----</option>
\t \t <option value="Maths">Maths</option>
\t \t <option value="Science">Science</option>
\t \t \t <option value="Computer Science">Computer Science</option>
\t \t <option value="Languages">English</option>
\t \t <option value="Others">Others</option>
</select>
PHP代码:
<?php
$dbhost = "localhost";// enter host
$dbuser = "root";// enter root
$dbpass = ""; // enter password
$dberror1 = "Could not connect to the database connection";
$dberror2 = "Could not connect to the database";
$conn = mysqli_connect($dbhost,$dbuser,$dbpass) or die ($dberror1);
$select_db = mysqli_select_db($conn,'your_database_name') or die ($dberror2);
$subject = $_POST['Subject'];
$sql = "INSERT INTO your_table_name (Subject) VALUES ('$subject')";
$result= mysqli_query($conn,$sql);
if($result){
echo "Enter is success.........";
}
?>
+1
感谢您的回复,但这不是我想要的。我想从复选框的下拉菜单中选择多个选项并将其插入到数据库中 –
什么是在这部分的错误?出现了什么错误。 –