从foreach循环输出中排除值

Question

我期望从foreach输出中排除特定值，其输出发生在friend_one或friend_two。我不想从我的查询中排除这个。

排除它在任一friend_one或friend_two发生将是$profile_user参数。我试图做到这一点if(in_array($friend_total_row->friend_one == $profile_user))，但我得到它的错误，再加上它只有friend_one在它。

任何人都有一个想法，我可以做到这一点？

<?php   
    //Friends --- total 
    $friend_status = 2; 
    $friend_sql = " 
     SELECT * 
     FROM friends 
     WHERE (friend_one = :profile_user or friend_two = :profile_user) 
     AND status = :total_status 
    "; 
    $friend_stmt = $con->prepare($friend_sql); 
    $friend_stmt->execute(array(':profile_user' => $profile_user, ':total_status' => $friend_status)); 
    $friend_total_rows = $friend_stmt->fetchAll(PDO::FETCH_ASSOC); 
    $count_total_friend = $friend_stmt->rowCount(); 
?> 
     <div id="friend-list-container"> 
      <div id="friend-list-count">Friends <span class="light-gray"><?php echo $count_total_friend; ?></span></div> 
      <div id="friend-list-image-container"> 
<?php   
    foreach ($friend_total_rows as $friend_total_row) { 
     if(in_array($friend_total_row->friend_one == $profile_user)) { 
      continue; 
     } 
     else { 
     $friend_1 = $friend_total_row['friend_one']; 
     $friend_2 = $friend_total_row['friend_two']; 
     //$friend_status  = $friend_total_row['status']; 
     //$friend_status_date = $friend_total_row['date']; 
     } 
     echo $friend_1 . $friend_2; 
    } 
?> 

我只是想从输出，这是其中X是排除$profile_user。然后我想要显示平方输出。

Answer 1

更新答案：

foreach ($friend_total_rows as $friend_total_row) { 
    $friend_1 = $friend_total_row['friend_one']; 
    $friend_2 = $friend_total_row['friend_two']; 

    if($friend_1 !== $profile_user) { 
     echo $friend_1; 
    } 

    if($friend_2 !== $profile_user) { 
     echo $friend_2; 
    } 
}