为什么快速排序功能更改参数值
问题描述:
我正在阅读递归部分的'ANSI-C编程语言'。我跑的递归例子:为什么快速排序功能更改参数值
#include <stdio.h>
#include <ctype.h>
#include <stdlib.h>
static int v[] = {1,3,6,1,2,3,6,89,3,5,7,2,3};
int size = sizeof(v)/sizeof(v[0]);
void sy_swap (int v[], int i, int j);
void sy_qsort(int v[], int left, int right);
/*Swap function*/
void sy_swap (int v[], int i, int j)
{
int temp;
temp = v[i];
v[i] = v[j];
v[j] = temp;
}
/*Sort function*/
void sy_qsort(int v[], int left, int right)
{
int i, last;
static int loop = 0;
if(left >= right){ /*Finish sort*/
return;
}
sy_swap(v, left, (left + right)/2); /*Move middle element to beginning of the half*/
last = left;
for(i = left+1; i<=right; i++){ /*After this loop, we have to half: smaller than 'middle element' and bigger*/
if (v[i] < v[left]){
sy_swap(v, ++last, i);
}
}
sy_swap(v, left, last); /*Move 'middle element' to the head of SMALL half, to finish division the array into 2 half*/
sy_qsort(v,left, last-1); /*Sort Small Half*/
sy_qsort(v, last+1, right); /*Sort Big Half*/
}
int main(void)
{
int i = 0;
printf("sizes: size of v=%d, size of v[0]=%d, total elements=%d\n",(int)sizeof(v), (int)sizeof(v[0]),size); /*Check 'size' before sort*/
sy_qsort(v,0,size);
printf("sizes: size of v=%d, size of v[0]=%d, total elements=%d\n",(int)sizeof(v), (int)sizeof(v[0]),size); /*Check 'size' after sort*/
for (i =0; i<size; i++){
printf("%d,",v[i]);
}
return (0);
}
难道有谁知道为什么“大小”变量被排序功能改变后,被称为尽管有几分函数内没有任何操作改变“正确”的说法?
这是结果表明,“尺寸”是从实际13至89(按数组元素的总数)(在阵列最大元素)
sizes: size of v=52, size of v[0]=4, total elements=13
sizes: size of v=52, size of v[0]=4, total **elements=89**
1,1,2,2,3,3,3,3,5,6,6,7,13,89,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0......
答
改变你未定义行为因为你包括该数组的size
作为有效索引,但事实并非如此。
采取例如环路
for(i = left+1; i<=right; i++)
在从main
函数在第一次调用sy_qsort
,可变right
等于size
这是阵列的尺寸,但作为一个指标是一个超越最后一个元素。条件需要是i < right
。
非常感谢,你是对的。由于left,right是arry中元素的索引,所以在调用sort函数时,它必须是:sy_qsort(v,0,size-1); – sydc