如何使用Kryo反序列化不可变集合？

Question

你如何反序列化不可变集合使用Kryo？除了我所做的事情之外，我还需要注册一些东西吗？

这里是我的示例代码

import com.esotericsoftware.kryo.Kryo 
import com.esotericsoftware.kryo.io.Input 
import com.esotericsoftware.kryo.io.Output 
import com.romix.scala.serialization.kryo._ 

val kryo = new Kryo 

// Serialization of Scala maps like Trees, etc 
kryo.addDefaultSerializer(classOf[scala.collection.Map[_,_]], classOf[ScalaMapSerializer]) 
kryo.addDefaultSerializer(classOf[scala.collection.generic.MapFactory[scala.collection.Map]], classOf[ScalaMapSerializer]) 

// Serialization of Scala sets 
kryo.addDefaultSerializer(classOf[scala.collection.Set[_]], classOf[ScalaSetSerializer]) 
kryo.addDefaultSerializer(classOf[scala.collection.generic.SetFactory[scala.collection.Set]], classOf[ScalaSetSerializer]) 

// Serialization of all Traversable Scala collections like Lists, Vectors, etc 
kryo.addDefaultSerializer(classOf[scala.collection.Traversable[_]], classOf[ScalaCollectionSerializer]) 

val filename = "c:\\aaa.bin" 
val ofile = new FileOutputStream(filename) 
val output2 = new BufferedOutputStream(ofile) 
val output = new Output(output2) 
kryo.writeClassAndObject(output, List("Test1", "Test2")) 
output.close() 

val ifile = new FileInputStream(filename) 
val input = new Input(new BufferedInputStream(ifile)) 
val deserialized = kryo.readClassAndObject(input) 
input.close() 

它抛出异常

Exception in thread "main" com.esotericsoftware.kryo.KryoException: Class cannot be created (missing no-arg constructor): scala.collection.immutable.$colon$colon 

Answer 1

尝试了这一点，因为它为我工作：FYI

import com.esotericsoftware.kryo.Kryo 
import com.esotericsoftware.kryo.io.Input 
import com.esotericsoftware.kryo.io.Output 
import com.romix.scala.serialization.kryo._ 
import org.objenesis.strategy.StdInstantiatorStrategy 

val kryo = new Kryo 

kryo.setRegistrationRequired(false) 
kryo.setInstantiatorStrategy(new StdInstantiatorStrategy()); 
kryo.register(classOf[scala.collection.immutable.$colon$colon[_]],60) 
kryo.register(classOf[scala.collection.immutable.Nil$],61) 
kryo.addDefaultSerializer(classOf[scala.Enumeration#Value], classOf[EnumerationSerializer]) 

val filename = "c:\\aaa.bin" 
val ofile = new FileOutputStream(filename) 
val output2 = new BufferedOutputStream(ofile) 
val output = new Output(output2) 
kryo.writeClassAndObject(output, List("Test1", "Test2")) 
output.close() 

val ifile = new FileInputStream(filename) 
val input = new Input(new BufferedInputStream(ifile)) 
val deserialized = kryo.readClassAndObject(input) 
input.close() 

作为，我得到了这个工作通过查看romix库的单元测试，然后做他们正在做的事情。