从文本文件中读取并将文字频率保存到新文本文件中，然后在新行上打印每个文件

Question

美好的一天。请帮助。使用的语言是python。下面的代码从一个文本文件中读取，然后将每个单词的频率返回到新行中。我是从这个网站https://rmtheis.wordpress.com/2012/09/26/count-word-frequency-with-python/

import re 
from collections import Counter 


def openfile(filename): 
    fh = open(filename, "r+") 
    str = fh.read() 
    fh.close() 
    return str 


def removegarbage(str): 
    # Replace one or more non-word (non-alphanumeric) chars with a space 
    str = re.sub(r'\W+', ' ', str) 
    str = str.lower() 
    return str 


def getwordbins(words): 
    cnt = Counter() 
    for word in words: 
     cnt[word] += 1 
    return cnt 


def main(filename, topwords): 
    txt = openfile(filename) 
    txt = removegarbage(txt) 
    words = txt.split(' ') 
    bins = getwordbins(words) 
    for key, value in bins.most_common(topwords): 

     print(key, value) 

main('hamlet.txt', 500) 

从上面的，它打印精美的IDE我使用（pyCharm）。但是，当我补充一点，上面的代码下面的下面的代码，

#Write to file 
    with open("newFile.txt", "w") as f: 
     for word in main('hamlet.txt', 500): 
      f.write(word + os.linesep) 

它打印在控制台不错，但显示了一些错误，也是它没写文本文件我创建在所有。 。下面是显示在控制台上的示例输出一个片段阅读的文本文件后，它打印：

the 16 
of 12 
to 9 
search 9 
which 6 

所以，现在，我希望写这上面的输出到纺织的文本文件。该内容要长得多比以上。谢谢。顺便说一句，误差在控制台上得到的是

Traceback (most recent call last): 
    File "/Users/test/PycharmProjects/Trial/trial.py", line 52, in <module> 
    for word in main("hamlet.txt", 500): 
TypeError: 'NoneType' object is not iterable 

Answer 1

，如果你想使用的功能main如图所示，即

for word in main('hamlet.txt', 500): 

那么函数应适应这一点。 人们可以使用例如发电机：

def main(filename, topwords): 
    txt = openfile(filename) 
    txt = removegarbage(txt) 
    words = txt.split(' ') 
    bins = getwordbins(words) 
    for key, value in bins.most_common(topwords): 
     # yield key #generate only the word, not it's frequency 
     yield key, value 

with open("newFile.txt", "w") as f: 
    for word, freq in main('hamlet.txt', 500): 
     f.write('%s\t%d\n' % (word, freq)) 

Answer 2

您需要return key, value，而不是打印出来