Mysqli更新命令不更新

问题描述：

include('config.php'); 
mysqli_select_db($mysqli, "real"); 
if ($transaction == "Success" && $currency == "USD") { 
    $user_ids = '".$user_id."'; $total_cred = `user_credits` +'".$package_credits."'; 
    $add = $mysqli->prepare("UPDATE `users` SET `user_credits` = ? WHERE `user_id` = ?"); 
    $add->bind_param('si', $total_cred,$user_ids); $add->execute(); 
}

该代码不会抛出任何错误，也不会更新数据库。Mysqli更新命令不更新

难道你不认为你的'$ total'说法有错误？ – hjpotter92 2013-02-12 09:39:59

总积分=（已存入积分）+购买的新积分。（''。$ package_credits。''）这是具有最近购买的学分的变量 – Shail 2013-02-12 09:42:32

这些表字段具有哪些数据类型？ – hjpotter92 2013-02-12 09:44:06

答

更改，如果块

// $user_ids = '".$user_id."'; REMOVE THE statement 
// $total_cred = `user_credits` + '".$package_credits."'; REMOVE THIS too 
$add = $mysqli->prepare("UPDATE `users` SET `user_credits` = `user_credits` + ? WHERE `user_id` = ?"); 
$add->bind_param('ii', $package_credits, $user_id); $add->execute();

让MySQL的做最困难的部分。

完美工作...感谢您的帮助 – Shail 2013-02-12 10:01:37

答

试试这个：

include('config.php'); 
mysqli_select_db($mysqli, "real"); 
if ($transaction == "Success" && $currency == "USD") 
{ 
    $user_ids = '".$user_id."'; 
    $total_cred = user_credits +'".$package_credits."'; 
    $add = $mysqli->prepare("UPDATE users SET user_credits = ? WHERE user_id = ?"); 
    $add->bind_param('si', $total_cred,$user_ids); 
    $add->execute(); 
}

Mysqli更新命令不更新

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