继承内部类Python3

Question

我需要的是这样的

class Parent(object): 
    class Base(object): 
     def __init__(self, a, b): 
      self.a = a 
      self.b = b 


    class Derived(Base): 
     def __init__(self, a, b, c): 
      super(Derived,self).__init__(a, b) 
      self.c = c 

     def doit(): 
      pass 

parent = Parent() 
derived = parent.Derived(x,y,z) 
derived.doit() 

当我尝试运行它，我得到这个以下错误：NameError: name 'Derived' is not defined

我的“衍生”的地方试图与“基地”在super() - 没有帮助

Answer 1

前缀“衍生”与“家长”，成功了。正如我已经评论过这个问题。这只是为了试验'派生'类。但我仍然想知道'派生类（Base）：'类是否正常（'Base'类没有'Parent。'前缀）

class Parent(object): 
    class Base(object): 
     def __init__(self, a, b): 
      self.a = a 
      self.b = b 


    class Derived(Base): 
     def __init__(self, a, b, c): 
      super(Parent.Derived,self).__init__(a, b) 
      self.c = c 

     def doit(): 
      pass 

parent = Parent() 
derived = parent.Derived(x,y,z) 
derived.doit() 

Answer 2

类的继承不会改变父类。在这种情况下，Parent类只包含原始的Base类，而不包含派生类。

您可以简单地使用猴子打补丁来解决这个问题，

class Parent(object): 
    pass 


class Base(object): 
    def __init__(self, a, b): 
     self.a = a 
     self.b = b 


class Derived(Base): 
    def __init__(self, a, b, c): 
     super(Derived,self).__init__(a, b) 
     self.c = c 

    def doit(self): 
     pass 

Parent.Derived = Derived 

parent = Parent() 
x, y , z = 1, 1, 1 
derived = parent.Derived(x,y,z) 
derived.doit()