无法解密使用gnupg中的openpgp-php加密的文件

问题描述：

我已经使用OpenPGP-PHP创建了公钥和私钥，然后我将它们两者都导入到GnuPG中，它不会导入公钥而不指定公钥“--allow-non-self-signed-uid”标志。然后，当我尝试解密文件，我得到以下几点：无法解密使用gnupg中的openpgp-php加密的文件

gpg --decrypt test.tif.asc 
Generated: Thu, 25 Feb 2016 11:12:28 -0500 
gpg: unknown armor header: 
By: <> 
gpg: unknown armor header: 
Using: OpenPGP for PHP 
gpg: unknown armor header: 
For: TEST 
gpg: unknown armor header: 
gpg: encrypted with 512-bit RSA key, ID 519A1973, created 2016-02-25 
     "TEST" 
gpg: public key decryption failed: Wrong secret key used 
gpg: decryption failed: No secret key

但关键明显存在：

gpg --list-secret-keys 
/home/mike/.gnupg/secring.gpg 
----------------------------- 
sec 512R/519A1973 2016-02-25 
uid     TEST

我生成它们与PHP代码：

$header = array(
     'Generated' => date("r"), 
     'By' => "Test <[email protected]>", 
     'Using' => "OpenPGP for PHP", 
     'For' => "TEST" 
      ); 

$rsa = new Crypt_RSA(); 
$k = $rsa->createKey(512); 
$rsa->loadKey($k['privatekey']); 

$nkey = new OpenPGP_SecretKeyPacket(array(
      'n' => $rsa->modulus->toBytes(), 
      'e' => $rsa->publicExponent->toBytes(), 
      'd' => $rsa->exponent->toBytes(), 
      'p' => $rsa->primes[1]->toBytes(), 
      'q' => $rsa->primes[2]->toBytes(), 
      'u' => $rsa->coefficients[2]->toBytes() 
      )); 

$uid = new OpenPGP_UserIDPacket("TEST"); 

$wkey = new OpenPGP_Crypt_RSA ($nkey); 
$m = $wkey->sign_key_userid(array($nkey, $uid)); 

// Serialize private key 
$private_bytes = $m->to_bytes(); 
$private_bytes = OpenPGP::enarmor($private_bytes, "PGP PRIVATE KEY BLOCK", $header); 

// Serialize public key message 
$pubm = clone($m); 
$pubm[0] = new OpenPGP_PublicKeyPacket($pubm[0]); 
$public_bytes = OpenPGP::enarmor($public_bytes, "PGP PUBLIC KEY BLOCK", $header);

而且加密使用：

$pgp_header = array(
     'Generated' => date("r"), 
     'By' => "Test <[email protected]>", 
     'Using' => "OpenPGP for PHP", 
     'For' => "TEST" 
     ); 

// Unarmor the public key for encrypting 
$public_bytes = OpenPGP_Message::parse(OpenPGP::unarmor($public_bytes, "PGP PUBLIC KEY BLOCK")); 

echo encryptData(file_get_contents("test.tif"), "test.tif", $public_bytes, $pgp_header); 

function encryptData($data, $filename, $key, $header) 
{ 
    $data = new OpenPGP_LiteralDataPacket($data, array('format' => 'u', 'filename' => $filename)); 
    $encrypted = OpenPGP_Crypt_Symmetric::encrypt($key, new OpenPGP_Message(array($data))); 

    return(OpenPGP::enarmor($encrypted->to_bytes(), "PGP MESSAGE", $header)); 
}

但它好像我肯定错过了某个地方的东西。我怎样才能让GnuPG成功解密我的东西？

“'$ RSA =新Crypt_RSA（）; $ķ = $ rsa-> createKey（512）;'“是否阻止RSA密钥大小

@ScottArciszewski将其提升到2048，仍然出现相同的错误！我将保留在2048，尽管如此， –

是$ public_bytes va可定义的riable？ 'OpenPGP :: unarmor（$ public_bytes，' –

答

首先：尝试使用由gpg生成的密钥使用OpenPGP-PHP进行加密 - 这是否行得通？（它对我来说是本地的。）

接下来，确保您生成的密钥具有0x04“加密通信”密钥标记集（您必须为此自己添加签名包，请在线路154上检查lib/openpgp_crypt_rsa.php 。看到默认生成的数据包，如果你不提供一个

而且，在凯基例如一个bug请升级至最新版本

无法解密使用gnupg中的openpgp-php加密的文件

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