Laravel查询生成器 - 如何使用连接格式化查询
问题描述:
我知道这是一个写得不好的查询。我如何使用Laravel查询构建器重新编写此代码?Laravel查询生成器 - 如何使用连接格式化查询
SELECT tgi.rate, tgi.tax_types_id, tt.name, tt.sales_chart_master_id, tt.purchase_chart_master_id
FROM tax_group_items tgi, tax_types tt
WHERE tgi.tax_groups_id = (SELECT tax_groups_id FROM customers WHERE id=2)
AND tt.id = tgi.tax_types_id
AND tt.id NOT IN (SELECT tax_types_id FROM item_tax_type_exemptions WHERE item_tax_types_id = (SELECT item_tax_types_id FROM products WHERE id = 1))
答
如果您在模型类中发布关系,答案会更容易,更清晰。如果您不知道如何定义关系,请转至官方文档的查询生成器部分。 如果你不想定义关系,或不想使用它们,然后用这个
$query = DB::select('your query');
答
DB::table(DB::raw('tax_group_items tgi, tax_types tt'))
->select(['tgi.rate', 'tgi.tax_types_id', 'tt.name', 'tt.sales_chart_master_id', 'tt.purchase_chart_master_id'])
->whereRaw('tgi.tax_groups_id = (SELECT tax_groups_id FROM customers WHERE id=2)')
->where('tt.id', 'tgi.tax_types_id')
->whereRaw('tt.id NOT IN (SELECT tax_types_id FROM item_tax_type_exemptions WHERE item_tax_types_id = (SELECT item_tax_types_id FROM products WHERE id = 1))')
->get();
发表您的口才型号太多 –
请发布模型类为好。 – PdC