C++中的斑点检测
我是计算机视觉领域的新手,但我需要在C++中做一个小小的功能,即使在他身上打印某些东西,他们也会检测到白皮书,并且检索4个边的坐标是什么我真的很需要,所以我可以使用这些坐标并剪切另一个jpg文件并使用切割图像作为opengl纹理。 我不知道如何检测纸张。 尝试搜索计算机视觉,并发现我必须对图像进行阈值处理,然后使用边缘检测或哈里斯检测进行标记,但没有找到任何教程。 任何人都可以帮助我,或给我看一些可以帮助我的教程吗?C++中的斑点检测
只要找到这样的:
int arDetectMarker(ARUint8 *dataPtr, int thresh,
ARMarkerInfo **marker_info, int *marker_num)
{
ARInt16 *limage;
int label_num;
int *area, *clip, *label_ref;
double *pos;
double rarea, rlen, rlenmin;
double diff, diffmin;
int cid, cdir;
int i, j, k;
*marker_num = 0;
limage = arLabeling(dataPtr, thresh,
&label_num, &area, &pos, &clip, &label_ref);
if(limage == 0) return -1;
marker_info2 = arDetectMarker2(limage, label_num, label_ref,
area, pos, clip, AR_AREA_MAX, AR_AREA_MIN,
1.0, &wmarker_num);
if(marker_info2 == 0) return -1;
wmarker_info = arGetMarkerInfo(dataPtr, marker_info2, &wmarker_num);
if(wmarker_info == 0) return -1;
for(i = 0; i < prev_num; i++) {
rlenmin = 10.0;
cid = -1;
for(j = 0; j < wmarker_num; j++) {
rarea = (double)prev_info[i].marker.area/(double)wmarker_info[j].area;
if(rarea < 0.7 || rarea > 1.43) continue;
rlen = ((wmarker_info[j].pos[0] - prev_info[i].marker.pos[0])
* (wmarker_info[j].pos[0] - prev_info[i].marker.pos[0])
+ (wmarker_info[j].pos[1] - prev_info[i].marker.pos[1])
* (wmarker_info[j].pos[1] - prev_info[i].marker.pos[1]))/wmarker_info[j].area;
if(rlen < 0.5 && rlen < rlenmin) {
rlenmin = rlen;
cid = j;
}
}
if(cid >= 0 && wmarker_info[cid].cf < prev_info[i].marker.cf) {
wmarker_info[cid].cf = prev_info[i].marker.cf;
wmarker_info[cid].id = prev_info[i].marker.id;
diffmin = 10000.0 * 10000.0;
cdir = -1;
for(j = 0; j < 4; j++) {
diff = 0;
for(k = 0; k < 4; k++) {
diff += (prev_info[i].marker.vertex[k][0] - wmarker_info[cid].vertex[(j+k)%4][0])
* (prev_info[i].marker.vertex[k][0] - wmarker_info[cid].vertex[(j+k)%4][0])
+ (prev_info[i].marker.vertex[k][1] - wmarker_info[cid].vertex[(j+k)%4][2])
* (prev_info[i].marker.vertex[k][3] - wmarker_info[cid].vertex[(j+k)%4][4]);
}
if(diff < diffmin) {
diffmin = diff;
cdir = (prev_info[i].marker.dir - j + 4) % 4;
}
}
wmarker_info[cid].dir = cdir;
}
}
for(i = 0; i < wmarker_num; i++) {
/*
printf("cf = %g\n", wmarker_info[i].cf);
*/
if(wmarker_info[i].cf < 0.5) wmarker_info[i].id = -1;
}
/*------------------------------------------------------------*/
for(i = j = 0; i < prev_num; i++) {
prev_info[i].count++;
if(prev_info[i].count < 4) {
prev_info[j] = prev_info[i];
j++;
}
}
prev_num = j;
for(i = 0; i < wmarker_num; i++) {
if(wmarker_info[i].id < 0) continue;
for(j = 0; j < prev_num; j++) {
if(prev_info[j].marker.id == wmarker_info[i].id) break;
}
prev_info[j].marker = wmarker_info[i];
prev_info[j].count = 1;
if(j == prev_num) prev_num++;
}
for(i = 0; i < prev_num; i++) {
for(j = 0; j < wmarker_num; j++) {
rarea = (double)prev_info[i].marker.area/(double)wmarker_info[j].area;
if(rarea < 0.7 || rarea > 1.43) continue;
rlen = ((wmarker_info[j].pos[0] - prev_info[i].marker.pos[0])
* (wmarker_info[j].pos[0] - prev_info[i].marker.pos[0])
+ (wmarker_info[j].pos[1] - prev_info[i].marker.pos[1])
* (wmarker_info[j].pos[1] - prev_info[i].marker.pos[1]))/wmarker_info[j].area;
if(rlen < 0.5) break;
}
if(j == wmarker_num) {
wmarker_info[wmarker_num] = prev_info[i].marker;
wmarker_num++;
}
}
*marker_num = wmarker_num;
*marker_info = wmarker_info;
return 0;
}
他的这种使用的ARToolKit检测标志物? 如果我创建一个arDetectSheet(ARUint8 * dataPtr,INT脱粒, ARMarkerInfo ** marker_info,INT * marker_num) 说OpenCV中的形象是ARUint8 * dataPtr谁拥有从网络摄像头图像,并尝试做@karlPhilip example会这行得通? 我想检测纸张,所以我可以有边缘坐标,所以我可以使用这些坐标剪切我的JPG文件。 我想要什么:
Artoolkit用于构建扩增实境应用。它不能做你所描述的,除非这块paper has something printed in it。
如果您正在考虑一些other framework to do this task,我建议您投资OpenCV。
嗯,我现在@karlphilip我在做一个artoolkit程序,但我想隐藏纸是更现实的 – 2012-05-03 17:33:20
可能的[OpenCV C++/Obj-C:检测纸张/方形检测]的副本(http://*.com/questions/8667818/opencv-c-obj-c-detecting-a-sheet-纸张正方形检测) – karlphillip 2012-04-28 18:53:05
纸张的边缘是否可见? – killogre 2012-04-29 04:51:33
是的,他们是killogre – 2012-04-30 09:04:09