通过HTTP POST方法在android系统

问题描述：

它不是DUPLICATE.Link发送JSON对象，已提供的是一个古老的“HTTP客户端”已api23被删除通过HTTP POST方法在android系统

我想送JSON对象：

{"emailId":"[email protected]","address":"Naya bans","city":"Noida","pincode":"201301","account_number":"91123546374208","bank_name":"Axis Bank","branch_name":"91123546374208","ifsc_code":"UTI0000879"}

到网址：

http://10digimr.mobimedia.in/api/mobile_retailer/update_profile 我该怎么做呢？通过post方法？

方法：

POST /api/mobile_retailer/update_profile

强制性KEY：

{"emailId","address"}

REQUEST JSON：

{"emailId":"[email protected]","address":"Naya bans","city":"Noida","pincode":"201301","account_number":"91123546374208","bank_name":"Axis Bank","branch_name":"91123546374208","ifsc_code":"UTI0000879"}

RESPONSE：

{"message":"Mail Send","data":true,"status":200}

你所提到的API是一个GET方法。请向API开发人员提供有关访问API的正确方法的文档。我试着通过休息客户端向它发送一个POSt请求。它给出了一个错误。 – crashOveride

可能的重复[如何发送一个JSON对象通过Android的请求？]（http://*.com/questions/3027066/how-to-send-a-json-object-over-request-with-android） –

我的不好！写错了网址！ – user6092109

答

定义类AsyncT并使用调用它onCreate方法：

AsyncT asyncT = new AsyncT(); 
asyncT.execute();

类定义：

class AsyncT extends AsyncTask<Void,Void,Void>{ 

     @Override 
     protected Void doInBackground(Void... params) { 

      try { 
       URL url = new URL(""); //Enter URL here 
       HttpURLConnection httpURLConnection = (HttpURLConnection)url.openConnection(); 
       httpURLConnection.setDoOutput(true); 
       httpURLConnection.setRequestMethod("POST"); // here you are telling that it is a POST request, which can be changed into "PUT", "GET", "DELETE" etc. 
       httpURLConnection.setRequestProperty("Content-Type", "application/json"); // here you are setting the `Content-Type` for the data you are sending which is `application/json` 
       httpURLConnection.connect(); 

       JSONObject jsonObject = new JSONObject(); 
       jsonObject.put("para_1", "arg_1"); 

       DataOutputStream wr = new DataOutputStream(httpURLConnection.getOutputStream()); 
       wr.writeBytes(jsonObject.toString()); 
       wr.flush(); 
       wr.close(); 

      } catch (MalformedURLException e) { 
       e.printStackTrace(); 
      } catch (IOException e) { 
       e.printStackTrace(); 
      } catch (JSONException e) { 
       e.printStackTrace(); 
      } 

      return null; 
     } 


    }

@gothdo你如何处理你从邮件中得到的回应？ –

通过HTTP POST方法在android系统

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