Laravel的卷曲错误18错误

Question

我有一个api和一个正在开发的客户端，都在laravel中，当我尝试使用guzzle连接到api时，出现错误18。

在我的API控制器我有这样的：

public function index() 
{ 
    $users = User::orderBy('username', 'asc'); 

    return Response::json(array(
     'error' => false, 
     'users' => $users->get()->toArray()), 
     200 
    ); 

} 

而且，如果我做卷曲--user [email protected]：密码http://myapi.api/api/v1/users

我得到一些正确需要我的控制台上的信息：

{"error":false,"users":[{"id":"1","firstname":"","lastname":"","username":"[email protected]","created_at":"2014-10-17 15:35:10","updated_at":"2014-10-17 15:35:10","client_id":"0","enterprise_id":"0","usertype_id":"0"},{"id":"2","firstname":"","lastname":"","username":"seconduser","created_at":"2014-10-17 15:35:10","updated_at":"2014-10-17 15:35:10","client_id":"0","enterprise_id":"0","usertype_id":"0"}]} 

的URL甚至还可以在浏览器（我得到一个弹出身份验证后我得到它的浏览器相同的输入）。所以这只是通过炫耀失败。

现在我的客户对我已经狂饮安装，我想这样的：

$client = new GuzzleHttp\Client(); 
$user='[email protected]'; 
$pass='password'; 

$res = $client->get('http://myapi.api/api/v1/users', array(
    'auth' => array('[email protected]', 'password') 
)); 

$users=$res->json(); 
$users=$users['users']; 

而我得到的错误：

[curl] (#18) See http://curl.haxx.se/libcurl/c/libcurl-errors.html for an explanation of cURL errors [url] http://myapi.api/api/v1/users 

我在做什么错？

编辑：在命令中使用-v我得到：

$ curl -v --user [email protected]:password http://myapi.api/api/v1/users 
* Hostname was NOT found in DNS cache 
* Trying 127.0.0.1... 
* Connected to myapi.api (127.0.0.1) port 80 (#0) 
* Server auth using Basic with user '[email protected]' 
> GET /api/v1/users HTTP/1.1 
> Authorization: Basic YWRtaW5AYWRtaW4uY29tOnBhc3N3b3Jk 
> User-Agent: curl/7.37.1 
> Host: myapi.api 
> Accept: */* 
> 
< HTTP/1.1 200 OK 
< Date: Mon, 20 Oct 2014 13:08:56 GMT 
* Server Apache/2.2.29 (Unix) mod_fastcgi/2.4.6 mod_wsgi/3.4 Python/2.7.8 PHP/5.5.17 mod_ssl/2.2.29 OpenSSL/0.9.8za DAV/2 mod_perl/2.0.8 Perl/v5.20.0 is not blacklisted 
< Server: Apache/2.2.29 (Unix) mod_fastcgi/2.4.6 mod_wsgi/3.4 Python/2.7.8 PHP/5.5.17 mod_ssl/2.2.29 OpenSSL/0.9.8za DAV/2 mod_perl/2.0.8 Perl/v5.20.0 
< X-Powered-By: PHP/5.5.17 
< Cache-Control: no-cache 
< Set-Cookie: laravel_session=eyJpdiI6IjRPMk9TT0ZnZklTMG1uWlFDancyMWc9PSIsInZhbHVlIjoic1V1RjA5aVBJdFNLM0JLclNROEE1a0dCeHNEMWhVNFVReTlUOHdidE44WEJzRnB4WFkxdWo0V0ozcXFVSW9LYzZiZzZSSlFCNXNTTjl2Mzh4TlFtTUE9PSIsIm1hYyI6IjhlYzY0YjFkNTQzNjk5ZGMxNDk3YmY4ZjU4YTYzYzM4YzgxZjg1MzlhMWUxNWVjYWE4ZThlMmU0N2RjNWFkZGMifQ%3D%3D; expires=Mon, 20-Oct-2014 15:08:57 GMT; Max-Age=7200; path=/; httponly 
< Transfer-Encoding: chunked 
< Content-Type: application/json 
< 
* Connection #0 to host myapi.api left intact 
{"error":false,"users":[{"id":"1","firstname":"","lastname":"","username":"[email protected]","created_at":"2014-10-17 15:35:10","updated_at":"2014-10-17 15:35:10","client_id":"0","enterprise_id":"0","usertype_id":"0"},{"id":"2","firstname":"","lastname":"","username":"seconduser","created_at":"2014-10-17 15:35:10","updated_at":"2014-10-17 15:35:10","client_id":"0","enterprise_id":"0","usertype_id":"0"} 

编辑：这个问题可能是过于具体，即使我还没有找到一个解决方案，并已走了不同的方式与这个项目，因为规格已经改变我会把它留在这里，以防它可以帮助某人。

我对答案的猜测是安德烈丹尼尔在评论中建议，认证正在破坏一些东西，并且不会给我我原来的json，从而产生错误。

Answer 1

在你的问题你说的这个URL通过命令行工作：

http://myapi.api/api/v1/users/1 

但你调用这个URL通过狂饮

http://myapi.api/api/v1/users 

那么，你确定你想打电话路线通过guzzle通过命令行工作？

Answer 2

我终于改变了方法，因为我们需要一种不同的身份验证方法，所以这个问题与我的情况不再相关。