如何编写以下CURL命令的php代码？

Question

如何编写以下CURL命令的php代码？

卷曲-H “授权：承载oVi4yPxk1bJ64Y2qOsLJ2D2ZlC3FpK4L” https://api.url.com/v1/market/total-items.json

Answer 1

我想你需要的东西是这样的：

<?php 

     $url = "https://api.url.com/v1/market/total-items.json"; 
     $page = "/v1/market/total-items.json"; 
     $headers = array( 
      "POST ".$page." HTTP/1.0", 
      "Authorization: Bearer oVi4yPxk1bJ64Y2qOsLJ2D2ZlC3FpK4L" 
     ); 

     $ch = curl_init(); 
     curl_setopt($ch, CURLOPT_URL,$url); 
     curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 
     curl_setopt($ch, CURLOPT_HTTPHEADER, $headers); 

     $data = curl_exec($ch); 

Answer 2

可以从github上branch这里生成的PHP代码为您的卷曲的命令。以下是为您的请求生成的一个：

<?php 
$ch = curl_init(); 

curl_setopt($ch, CURLOPT_URL, "https://api.url.com/v1/market/total-items.json"); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "GET"); 


$headers = array(); 
$headers[] = "Authorization: Bearer oVi4yPxk1bJ64Y2qOsLJ2D2ZlC3FpK4L"; 
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers); 

$result = curl_exec($ch); 
if (curl_errno($ch)) { 
    echo 'Error:' . curl_error($ch); 
} 
curl_close ($ch);